Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Divide. If there is a remainder, include it as a simplified fraction.\newline(18j2+8j)÷2j(18j^2 + 8j) \div 2j

Full solution

Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(18j2+8j)÷2j(18j^2 + 8j) \div 2j
  1. Divide by 22j: We have the expression to divide: \newline(18j2+8j)÷2j(18j^2 + 8j) \div 2j\newlineFirst, we will divide each term in the polynomial by the monomial 2j2j.\newline(18j2+8j)÷2j=18j22j+8j2j(18j^2 + 8j) \div 2j = \frac{18j^2}{2j} + \frac{8j}{2j}
  2. Divide first term: Now let's divide the first term:\newline(18j2)/(2j)=18/2×j2/j=9j(18j^2)/(2j) = 18/2 \times j^2/j = 9j\newlineWe have divided the coefficient 1818 by 22 and reduced the powers of jj by subtracting the exponents (21=1)(2 - 1 = 1).
  3. Divide second term: Next, we divide the second term:\newline(8j)/(2j)=8/2×j/j=4(8j)/(2j) = 8/2 \times j/j = 4\newlineHere, we have divided the coefficient 88 by 22 and canceled out the jj terms since they are the same in the numerator and denominator.
  4. Combine results: Combining the results from the two divisions, we get:\newline(18j2+8j)÷2j=9j+4(18j^2 + 8j) \div 2j = 9j + 4\newlineThis is the simplified form of the expression, with no remainder.

More problems from Divide polynomials by monomials