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Divide. If there is a remainder, include it as a simplified fraction.\newline(u25u6)÷(u6)(u^2 - 5u - 6) \div (u - 6)

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Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(u25u6)÷(u6)(u^2 - 5u - 6) \div (u - 6)
  1. Divide Leading Terms: We have the division problem: \newline(u25u6)÷(u6)(u^2 - 5u - 6) \div (u - 6)\newlineTo solve this, we will perform polynomial long division.
  2. Multiply and Subtract: First, we divide the leading term of the numerator, u2u^2, by the leading term of the denominator, uu, to get the first term of the quotient.\newlineu2÷u=uu^2 \div u = u
  3. Correcting Mistake: Next, we multiply the entire denominator (u6)(u - 6) by the term we just found, uu, and subtract the result from the original polynomial.(u6)u=u26u(u - 6) \cdot u = u^2 - 6uSubtract this from the original polynomial:(u25u6)(u26u)=u(u^2 - 5u - 6) - (u^2 - 6u) = u
  4. Correcting Mistake: Next, we multiply the entire denominator (u6)(u - 6) by the term we just found, uu, and subtract the result from the original polynomial.(u6)u=u26u(u - 6) \cdot u = u^2 - 6uSubtract this from the original polynomial:(u25u6)(u26u)=u(u^2 - 5u - 6) - (u^2 - 6u) = uWe made a mistake in the previous step. We need to subtract the entire expression, not just the uu term. Let's correct this.(u25u6)(u26u)=5u6(6u)=u6(u^2 - 5u - 6) - (u^2 - 6u) = -5u - 6 - (-6u) = u - 6

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