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Divide. If there is a remainder, include it as a simplified fraction.\newline(3s3+26s2+48s)÷(s+6)(3s^3 + 26s^2 + 48s) \div (s + 6)\newline______

Full solution

Q. Divide. If there is a remainder, include it as a simplified fraction.\newline(3s3+26s2+48s)÷(s+6)(3s^3 + 26s^2 + 48s) \div (s + 6)\newline______
  1. Use Polynomial Long Division: To divide the polynomial 3s3+26s2+48s3s^3 + 26s^2 + 48s by the binomial s+6s + 6, we will use polynomial long division.
  2. Find First Quotient Term: First, we divide the leading term of the polynomial, 3s33s^3, by the leading term of the binomial, ss, to get the first term of the quotient, which is 3s23s^2.
  3. Subtract and Find Remainder: Next, we multiply the entire binomial (s+6)(s + 6) by the term we just found, 3s23s^2, to get 3s3+18s23s^3 + 18s^2. We then subtract this from the original polynomial to find the remainder.\newline(3s3+26s2+48s)(3s3+18s2)=8s2+48s(3s^3 + 26s^2 + 48s) - (3s^3 + 18s^2) = 8s^2 + 48s.
  4. Find Next Quotient Term: Now, we divide the leading term of the new remainder, 8s28s^2, by the leading term of the binomial, ss, to get the next term of the quotient, which is 8s8s.
  5. Subtract and Check Remainder: We multiply the binomial (s+6)(s + 6) by 8s8s to get 8s2+48s8s^2 + 48s and subtract this from the remainder we had.\newline(8s2+48s)(8s2+48s)=0(8s^2 + 48s) - (8s^2 + 48s) = 0.
  6. Finalize Quotient: Since the remainder is 00, we have no remainder in our division, and the quotient is the final answer.

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