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Direct Messages - SEQTA Le
Assessment Master - Exam Wi
assess.scsa.wa.edu.au/engine/index.php/Ims/index
School Curriculum
and Standards
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Numeracy
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31751624
43 of 45
In a board game, two standard dice are thrown.
The top numbers are then added to determine the number of spaces a player moves.
To land on a blue space, Ben must throw a total of 8 or 9 on his next turn. What is the probability that Ben would land on a blue space?

(2)/(36)

(5)/(36)

(9)/(36)

(10)/(36)
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Direct Messages - SEQTA Le\newlineAssessment Master - Exam Wi\newlineassess.scsa.wa.edu.au/engine/index.php/Ims/index\newlineSchool Curriculum\newlineand Standards\newlineAuthority\newlineNumeracy\newline() 00:1111:5858 / 00:5050:0000\newline3175162431751624\newline4343 of 4545\newlineIn a board game, two standard dice are thrown.\newlineThe top numbers are then added to determine the number of spaces a player moves.\newlineTo land on a blue space, Ben must throw a total of 88 or 99 on his next turn. What is the probability that Ben would land on a blue space?\newline236 \frac{2}{36} \newline536 \frac{5}{36} \newline936 \frac{9}{36} \newline1036 \frac{10}{36} \newlineContent copyright WA School Curriculum and Standards Authority 20242024\newlinea a \newlineAssessment\newlineCopyright \oplus SoNET Systems Pty Ltd. 20242024\newline(.)\newlineMaster

Full solution

Q. Direct Messages - SEQTA Le\newlineAssessment Master - Exam Wi\newlineassess.scsa.wa.edu.au/engine/index.php/Ims/index\newlineSchool Curriculum\newlineand Standards\newlineAuthority\newlineNumeracy\newline() 00:1111:5858 / 00:5050:0000\newline3175162431751624\newline4343 of 4545\newlineIn a board game, two standard dice are thrown.\newlineThe top numbers are then added to determine the number of spaces a player moves.\newlineTo land on a blue space, Ben must throw a total of 88 or 99 on his next turn. What is the probability that Ben would land on a blue space?\newline236 \frac{2}{36} \newline536 \frac{5}{36} \newline936 \frac{9}{36} \newline1036 \frac{10}{36} \newlineContent copyright WA School Curriculum and Standards Authority 20242024\newlinea a \newlineAssessment\newlineCopyright \oplus SoNET Systems Pty Ltd. 20242024\newline(.)\newlineMaster
  1. Identify outcomes: Identify all possible outcomes when two dice are thrown. There are 66 faces on each die, so the total number of outcomes is 6×6=366 \times 6 = 36.
  2. Calculate favorable outcomes for 88: Calculate the number of favorable outcomes for throwing a total of 88. The combinations are (2,6)(2,6), (3,5)(3,5), (4,4)(4,4), (5,3)(5,3), (6,2)(6,2). That's 55 ways.
  3. Calculate favorable outcomes for 99: Calculate the number of favorable outcomes for throwing a total of 99. The combinations are (3,6)(3,6), (4,5)(4,5), (5,4)(5,4), (6,3)(6,3). That's 44 ways.
  4. Add favorable outcomes: Add the favorable outcomes for 88 and 99. Total favorable outcomes =5= 5 (for 88) +4+ 4 (for 99) =9= 9.
  5. Calculate probability: Calculate the probability. Probability = Number of favorable outcomes / Total number of outcomes = 936\frac{9}{36}. This simplifies to 14\frac{1}{4}, but we need to check the given options.

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