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Dina is conducting a study on the amount of electricity used per person in the country of Qatar. She finds that from the year 20002000 to 20082008, the amount of electricity used per person grew by an average of 6%6\% from one year to the next. Let e(t)e(t) be the amount of electricity used per person in kilowatt-hours and tt the number of years after 20002000. If the amount of electricity used per person in 20002000 was approximately 12,30012,300 kilowatt-hours, which of the following mathematical models will give Dana how much electricity was used per person between 20002000 and 20082008?

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Q. Dina is conducting a study on the amount of electricity used per person in the country of Qatar. She finds that from the year 20002000 to 20082008, the amount of electricity used per person grew by an average of 6%6\% from one year to the next. Let e(t)e(t) be the amount of electricity used per person in kilowatt-hours and tt the number of years after 20002000. If the amount of electricity used per person in 20002000 was approximately 12,30012,300 kilowatt-hours, which of the following mathematical models will give Dana how much electricity was used per person between 20002000 and 20082008?
  1. Identify Initial Data: Identify the initial amount of electricity used and the growth rate.\newlineInitial electricity usage in 20002000: 12,30012,300 kilowatt-hours.\newlineAnnual growth rate: 6%6\%.
  2. Use Exponential Growth Formula: Use the formula for exponential growth to model the electricity usage.\newlineThe formula for exponential growth is e(t)=e0×(1+r)t e(t) = e_0 \times (1 + r)^t where:\newline- e0 e_0 is the initial amount (1212,300300 kilowatt-hours),\newline- r r is the growth rate (00.0606),\newline- t t is the number of years after 20002000.
  3. Calculate Electricity Usage in 20082008: Calculate the amount of electricity used in 20082008, which is 88 years after 20002000.\newlinePlug in the values into the formula: e(8)=12,300×(1+0.06)8 e(8) = 12,300 \times (1 + 0.06)^8 .
  4. Perform Calculation: Perform the calculation.\newlinee(8)=12,300×1.068 e(8) = 12,300 \times 1.06^8 \newlinee(8)=12,300×1.59385 e(8) = 12,300 \times 1.59385 (using a calculator for 1.068 1.06^8 )\newlinee(8)=19,604.345 e(8) = 19,604.345 kilowatt-hours.

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