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Diketahui vektor-vektor sebagai berikut :

{:[u=[1","-2","3]],[v=[5","6","-1]],[w=[3","2","1]]:}

(15 poin) Apakah vektor 
z=[0,16,-16] merupakan kombinasi linier dari vektorvektor 
u,v, dan 
w ?

Diketahui vektor-vektor sebagai berikut :\newlineu=[1,2,3]v=[5,6,1]w=[3,2,1] \begin{array}{l} \mathbf{u}=[1,-2,3] \\ \mathbf{v}=[5,6,-1] \\ \mathbf{w}=[3,2,1] \end{array} \newline11. (1515 poin) Apakah vektor z=[0,16,16] \mathbf{z}=[0,16,-16] merupakan kombinasi linier dari vektorvektor u,v \mathbf{u}, \mathbf{v} , dan w \mathbf{w} ?

Full solution

Q. Diketahui vektor-vektor sebagai berikut :\newlineu=[1,2,3]v=[5,6,1]w=[3,2,1] \begin{array}{l} \mathbf{u}=[1,-2,3] \\ \mathbf{v}=[5,6,-1] \\ \mathbf{w}=[3,2,1] \end{array} \newline11. (1515 poin) Apakah vektor z=[0,16,16] \mathbf{z}=[0,16,-16] merupakan kombinasi linier dari vektorvektor u,v \mathbf{u}, \mathbf{v} , dan w \mathbf{w} ?
  1. Set up equations: To determine if zz is a linear combination of uu, vv, and ww, we need to solve the equation au+bv+cw=zau + bv + cw = z for scalars aa, bb, and cc.
  2. Solve for aa: Set up the system of linear equations based on the components of the vectors:\newline1a+5b+3c=01a + 5b + 3c = 0 (x-components)\newline2a+6b+2c=16-2a + 6b + 2c = 16 (y-components)\newline3a1b+1c=163a - 1b + 1c = -16 (z-components)
  3. Substitute aa into equations: Solve the first equation for aa: a=5b3ca = -5b - 3c.
  4. Simplify equations: Substitute aa into the second and third equations:\newline2(5b3c)+6b+2c=16-2(-5b - 3c) + 6b + 2c = 16\newline3(5b3c)1b+1c=163(-5b - 3c) - 1b + 1c = -16
  5. Combine like terms: Simplify the equations:\newline10b+6c+6b+2c=1610b + 6c + 6b + 2c = 16\newline15b9c1b+1c=16-15b - 9c - 1b + 1c = -16
  6. Solve system of equations: Combine like terms: \newline16b+8c=1616b + 8c = 16\newline16b8c=16-16b - 8c = -16
  7. Solve system of equations: Combine like terms:\newline16b+8c=1616b + 8c = 16\newline16b8c=16-16b - 8c = -16 Solve the system of equations. Multiply the second equation by 1-1 to make it easier to add them together:\newline16b+8c=1616b + 8c = 16\newline16b+8c=1616b + 8c = 16

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