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Dianelys deposits 
$6,100 every year into an account earning an annual interest rate of 
5% compounded annually. How much would she have in the account after 4 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Dianelys deposits $6,100 \$ 6,100 every year into an account earning an annual interest rate of 5% 5 \% compounded annually. How much would she have in the account after 44 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Dianelys deposits $6,100 \$ 6,100 every year into an account earning an annual interest rate of 5% 5 \% compounded annually. How much would she have in the account after 44 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify variables: Identify the variables from the problem to use in the formula.\newlineWe have:\newlined=$6,100d = \$6,100 (the amount invested at the end of each period)\newlinei=5%i = 5\% or 0.050.05 (the interest rate per period)\newlinen=4n = 4 (the number of periods)
  2. Convert interest rate: Convert the percentage interest rate to a decimal. i=5%=5100=0.05i = 5\% = \frac{5}{100} = 0.05
  3. Plug values into formula: Plug the values into the compound interest formula to calculate the future value of the account.\newlineA=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^n - 1\right) / i\newlineA=6100×((1+0.05)41)/0.05A = 6100 \times \left(\left(1 + 0.05\right)^4 - 1\right) / 0.05
  4. Calculate compound factor: Calculate the compound factor (1+i)n(1 + i)^n.(1+i)n=(1+0.05)4(1 + i)^n = (1 + 0.05)^4(1+i)n=1.054(1 + i)^n = 1.05^4(1+i)n1.21550625(1 + i)^n \approx 1.21550625
  5. Calculate numerator: Calculate the numerator of the formula: ((1+i)n1)((1 + i)^n - 1).
    ((1+i)n1)1.215506251((1 + i)^n - 1) \approx 1.21550625 - 1
    ((1+i)n1)0.21550625((1 + i)^n - 1) \approx 0.21550625
  6. Calculate future value: Calculate the future value of the account using the formula.\newlineA6100×(0.21550625/0.05)A \approx 6100 \times (0.21550625 / 0.05)\newlineA6100×4.310125A \approx 6100 \times 4.310125\newlineA26291.7625A \approx 26291.7625
  7. Round to nearest dollar: Round the future value to the nearest dollar. \newlineA$26,292A \approx \$26,292

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