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Determine whether the lines are parallel, perpendicular or neither.

{:[y=(3)/(4)x+2],[8x+6y=12]:}
Parallel

Determine whether the lines are parallel, perpendicular or neither.\newliney=34x+28x+6y=12 \begin{array}{l} y=\frac{3}{4} x+2 \\ 8 x+6 y=12 \end{array} \newlineParallel \newlineperpendicular \newlineneither

Full solution

Q. Determine whether the lines are parallel, perpendicular or neither.\newliney=34x+28x+6y=12 \begin{array}{l} y=\frac{3}{4} x+2 \\ 8 x+6 y=12 \end{array} \newlineParallel \newlineperpendicular \newlineneither
  1. Find Slope First Line: To determine the relationship between the two lines, we need to find their slopes. If the slopes are equal, the lines are parallel. If the product of the slopes is 1-1, the lines are perpendicular. Otherwise, they are neither parallel nor perpendicular.
  2. Find Slope Second Line: First, let's find the slope of the first line given by y=34x+2y=\frac{3}{4}x+2. The slope-intercept form of a line is y=mx+by=mx+b, where mm is the slope. Here, the slope mm is clearly 34\frac{3}{4}.
  3. Determine Relationship: Now, let's find the slope of the second line given by 8x+6y=128x+6y=12. We need to rearrange this equation into slope-intercept form, y=mx+by=mx+b. Let's solve for yy.
  4. Isolate y Term: Subtract 8x8x from both sides of the equation 8x+6y=128x+6y=12 to isolate the yy term on one side:\newline6y=8x+126y = -8x + 12
  5. Solve for y: Now, divide both sides of the equation by 66 to solve for y: y=86x+126y = \frac{-8}{6}x + \frac{12}{6}
  6. Simplify Fractions: Simplify the fractions:\newliney=43x+2y = \frac{-4}{3}x + 2\newlineThe slope of the second line is 43-\frac{4}{3}.
  7. Check Parallel Lines: Now we have the slopes of both lines: the first line has a slope of 34\frac{3}{4}, and the second line has a slope of 43-\frac{4}{3}. Since these slopes are not equal, the lines are not parallel. To check if they are perpendicular, we multiply the slopes and see if the product is 1-1.
  8. Calculate Slope Product: Multiply the slopes (34)×(43)(\frac{3}{4}) \times (-\frac{4}{3}):(\frac{\(3\)}{\(4\)}) \times (-\frac{\(4\)}{\(3\)}) = \(-1
  9. Lines are Perpendicular: The product of the slopes is 1-1, which means the lines are perpendicular to each other.

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