Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Determine the minimum value of y=(x5)2y=(x-5)^2

Full solution

Q. Determine the minimum value of y=(x5)2y=(x-5)^2
  1. Recognize Quadratic Function: To find the minimum value of the function y=(x5)2y=(x-5)^2, we need to recognize that this is a quadratic function in the form of y=a(xh)2+ky=a(x-h)^2+k, where (h,k)(h,k) is the vertex of the parabola. Since aa is positive (a=1a=1), the parabola opens upwards, and the vertex represents the minimum point of the function.
  2. Find Vertex Coordinates: The vertex of the parabola is given by the point (h,k)(h,k). In the function y=(x5)2y=(x-5)^2, h=5h=5 and k=0k=0, because the function can be rewritten as y=1(x5)2+0y=1*(x-5)^2+0. Therefore, the vertex is at the point (5,0)(5,0).
  3. Determine Minimum Value: Since the vertex (5,0)(5,0) represents the lowest point on the graph of the function y=(x5)2y=(x-5)^2, the minimum value of yy is the yy-coordinate of the vertex. Therefore, the minimum value of yy is 00.

More problems from Factor sums and differences of cubes