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Determine the equation through the lines through the points (21,5)(-21,5) and (7,13)(7,13)

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Q. Determine the equation through the lines through the points (21,5)(-21,5) and (7,13)(7,13)
  1. Calculate Slope: Given points: \newline(21,5)(-21, 5) and \newline(7,13)(7, 13) \newlineFind the slope of the line using the points. \newlineSlope, mm \newline=y2y1x2x1= \frac{y_2 - y_1}{x_2 - x_1} \newline=1357(21)= \frac{13 - 5}{7 - (-21)} \newline=828= \frac{8}{28} \newline=27= \frac{2}{7} \newlineSo, m=27m = \frac{2}{7}
  2. Find Y-Intercept: We have: \newlinem:27m: \frac{2}{7} \newlinePoint: (7,13)(7, 13) \newlineFind the value of bb, the y-intercept. \newlineSubstitute x=7x = 7, y=13y = 13, and m=27m = \frac{2}{7} in y=mx+by = mx + b. \newline13=(27)(7)+b13 = \left(\frac{2}{7}\right)(7) + b \newline13=2+b13 = 2 + b \newline132=b13 - 2 = b \newline(7,13)(7, 13)00 \newlineSo, (7,13)(7, 13)11
  3. Write Equation: We found: \newlinem:27m: \frac{2}{7} \newlineb:11b: 11 \newlineWrite the equation of the line in slope-intercept form. \newlineSubstitute m=27m = \frac{2}{7} and b=11b = 11 in y=mx+by = mx + b. \newliney=(27)x+11y = \left(\frac{2}{7}\right)x + 11 \newlineSlope-intercept form: y=(27)x+11y = \left(\frac{2}{7}\right)x + 11

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