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Design an Ultimate Circle!
Name:

qquad Answer Key
Given information: 
MRV=74quad mWP=3quad Q is tangent to 
X at 
U

x is the center 
mzS=5quad mPO=9

2y is the diameter 
MSU=8quad MQR=4
m 
260=60mUY=46m omega S=16m/_WPO=50
(1) Inscribed Angle/Arc:

m/_ZU omega=66//2=33^(@)
(4) Central Angle / Arc:

m/_z × W=66^(@)

{:[" (3) Tangent / Chord: "],[m/_WUN=180-66=114],[114+46=160],[160//2=80^(@)1]:}
(10)
Angles inside circle:

{:[m/_UVY=(66+46)/(2)],[112//2=156^(@)∣]:}
Angles outside circle

m/_RQU=180-66=114

114+46=160quad(160-74)/(2)=|43^(@)|
Seyment of chords:

{:[m bar(RS)=10 x=5(8)],[10 x=40quad x=14]:}
(2) Segment of secants:

{:[" mYO "=51=16+4x],[35=4y],[x=18.751]:}
(5)
segment of secants and tangents:

m bar(QU)=
(2)
Triangle sum theor 
m/_QSU=
Answers:
O Anna Taylor
http://www.teacherspayteachers.com/store/piece-of.-Pi

Design an Ultimate Circle!\newlineName:\newline \qquad Answer Key\newlineGiven information: MRV=74mWP=3Q M R V=74 \quad m W P=3 \quad Q is tangent to X X at U U \newlinex x is the center mzS=5mPO=9 m z S=5 \quad m P O=9 \newline2y 2 y is the diameter MSU=8MQR=4 M S U=8 \quad M Q R=4 \newlinem 260=60 mUY=46mωS=16 mWPO=50 260=60 \mathrm{~m} U Y=46 \mathrm{m \omega S}=16 \mathrm{~m} \angle \mathrm{WPO}=50 \newline(11) Inscribed Angle/Arc:\newlinemZUω=66/2=33 m \angle Z U \omega=66 / 2=33^{\circ} \newline(44) Central Angle / Arc:\newlinemz×W=66 m \angle z \times W=66^{\circ} \newline (3) Tangent / Chord: mWUN=18066=114114+46=160160/2=801 \begin{array}{l} \text { (3) Tangent / Chord: } \\ m \angle W U N=180-66=114 \\ 114+46=160 \\ 160 / 2=80^{\circ} 1 \end{array} \newline(1010)\newlineAngles inside circle:\newlinemUVY=66+462112/2=156 \begin{array}{l} m \angle U V Y=\frac{66+46}{2} \\ 112 / 2=156^{\circ} \mid \end{array} \newlineAngles outside circle\newlinemRQU=18066=114 m \angle R Q U=180-66=114 \newline114+46=160160742=43 114+46=160 \quad \frac{160-74}{2}=\left|43^{\circ}\right| \newlineSeyment of chords:\newlinemRS=10x=5(8)10x=40x=14 \begin{array}{l} m \overline{R S}=10 x=5(8) \\ 10 x=40 \quad x=14 \end{array} \newline(22) Segment of secants:\newline mYO =51=16+4x35=4yx=18.751 \begin{aligned} \text { mYO }=51 & =16+4 x \\ 35 & =4 y \\ x & =18.751 \end{aligned} \newline(55)\newlinesegment of secants and tangents:\newlinemQU= m \overline{Q U}= \newline(22)\newlineTriangle sum theor MRV=74mWP=3Q M R V=74 \quad m W P=3 \quad Q 00\newlineAnswers:\newlineO Anna Taylor\newlinehttp://www.teacherspayteachers.com/store/piece-of.-Pi

Full solution

Q. Design an Ultimate Circle!\newlineName:\newline \qquad Answer Key\newlineGiven information: MRV=74mWP=3Q M R V=74 \quad m W P=3 \quad Q is tangent to X X at U U \newlinex x is the center mzS=5mPO=9 m z S=5 \quad m P O=9 \newline2y 2 y is the diameter MSU=8MQR=4 M S U=8 \quad M Q R=4 \newlinem 260=60 mUY=46mωS=16 mWPO=50 260=60 \mathrm{~m} U Y=46 \mathrm{m \omega S}=16 \mathrm{~m} \angle \mathrm{WPO}=50 \newline(11) Inscribed Angle/Arc:\newlinemZUω=66/2=33 m \angle Z U \omega=66 / 2=33^{\circ} \newline(44) Central Angle / Arc:\newlinemz×W=66 m \angle z \times W=66^{\circ} \newline (3) Tangent / Chord: mWUN=18066=114114+46=160160/2=801 \begin{array}{l} \text { (3) Tangent / Chord: } \\ m \angle W U N=180-66=114 \\ 114+46=160 \\ 160 / 2=80^{\circ} 1 \end{array} \newline(1010)\newlineAngles inside circle:\newlinemUVY=66+462112/2=156 \begin{array}{l} m \angle U V Y=\frac{66+46}{2} \\ 112 / 2=156^{\circ} \mid \end{array} \newlineAngles outside circle\newlinemRQU=18066=114 m \angle R Q U=180-66=114 \newline114+46=160160742=43 114+46=160 \quad \frac{160-74}{2}=\left|43^{\circ}\right| \newlineSeyment of chords:\newlinemRS=10x=5(8)10x=40x=14 \begin{array}{l} m \overline{R S}=10 x=5(8) \\ 10 x=40 \quad x=14 \end{array} \newline(22) Segment of secants:\newline mYO =51=16+4x35=4yx=18.751 \begin{aligned} \text { mYO }=51 & =16+4 x \\ 35 & =4 y \\ x & =18.751 \end{aligned} \newline(55)\newlinesegment of secants and tangents:\newlinemQU= m \overline{Q U}= \newline(22)\newlineTriangle sum theor MRV=74mWP=3Q M R V=74 \quad m W P=3 \quad Q 00\newlineAnswers:\newlineO Anna Taylor\newlinehttp://www.teacherspayteachers.com/store/piece-of.-Pi
  1. Calculate angle ZUωZU\omega: Calculate the measure of angle ZUωZU\omega using the Inscribed Angle Theorem, which states that the measure of an inscribed angle is half the measure of its intercepted arc.mZUω=66°2=33°m\angle ZU\omega = \frac{66°}{2} = 33°
  2. Determine angle z×Wz \times W: Determine the measure of angle z×Wz \times W using the fact that it is a central angle and equal to the measure of its intercepted arc.\newlinemz×W=66m\angle z \times W = 66^\circ
  3. Find angle WUN: Find the measure of angle WUN using the Tangent/Chord Theorem, which states that the angle formed by a tangent and a chord is half the sum of the intercepted arcs.\newlinemWUN=(18066)+46=160m\angle WUN = (180^\circ - 66^\circ) + 46^\circ = 160^\circ