Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

DeltaMath Student Application 3010254//23346821//dc 5986 c 636 e2a 375955 c 422635 d1ce4d hagorean Theorem Word Problems ore: 0//10 Penalty: 1 off Question Show Examples An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and twc congruent triangles. As a result, the altitude cuts the base into two equal segments. The length of the altitude is 26 inches, and the length of the base is 9 inches. Find the triangle's perimeter. Round to the nearest tenth of an inch. Answer Attempt 1 out of 2 ◻ in. Submit Answer

DeltaMath Student Application\newline3010254/23346821/dc5986c636e2a375955c422635d1ce4d 3010254 / 23346821 / d c 5986 c 636 e 2 a 375955 c 422635 d 1 c e 4 d \newlinehagorean Theorem Word Problems\newlineore: 0/10 0 / 10 \newlinePenalty: 11 off\newlineQuestion\newlineShow Examples\newlineAn altitude is drawn from the vertex of an isosceles triangle, forming a right angle and twc congruent triangles. As a result, the altitude cuts the base into two equal segments. The length of the altitude is 2626 inches, and the length of the base is 99 inches. Find the triangle's perimeter. Round to the nearest tenth of an inch.\newlineAnswer Attempt 11 out of 22\newline□ \square in.\newlineSubmit Answer

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Pythagorean Theorem and its converseright chevron icon

Full solution

Q. DeltaMath Student Application\newline3010254/23346821/dc5986c636e2a375955c422635d1ce4d 3010254 / 23346821 / d c 5986 c 636 e 2 a 375955 c 422635 d 1 c e 4 d \newlinehagorean Theorem Word Problems\newlineore: 0/10 0 / 10 \newlinePenalty: 11 off\newlineQuestion\newlineShow Examples\newlineAn altitude is drawn from the vertex of an isosceles triangle, forming a right angle and twc congruent triangles. As a result, the altitude cuts the base into two equal segments. The length of the altitude is 2626 inches, and the length of the base is 99 inches. Find the triangle's perimeter. Round to the nearest tenth of an inch.\newlineAnswer Attempt 11 out of 22\newline□ \square in.\newlineSubmit Answer
  1. Calculate Distance Kimi-School: Calculate the distance from Kimi's house to school.\newlineDistance = 15 km15\,\text{km}
  2. Calculate Distance School-Franklin: Calculate the distance from school to Franklin's house.\newlineDistance = 8 km8\,\text{km}
  3. Use Pythagorean Theorem: Use the Pythagorean Theorem to find the distance from Franklin's house to Kimi's house.\newlinea2+b2=c2a^2 + b^2 = c^2\newline152+82=c215^2 + 8^2 = c^2\newline225+64=c2225 + 64 = c^2\newline289=c2289 = c^2\newlinec=289c = \sqrt{289}\newlinec=17 kmc = 17 \text{ km}
  4. Find Total Bicycling Distance: Add up all the distances to find the total distance Kimi bicycles.\newlineTotal distance = 15 km+8 km+17 km15 \, \text{km} + 8 \, \text{km} + 17 \, \text{km}\newlineTotal distance = 40 km40 \, \text{km}

More problems from Pythagorean Theorem and its converse

Question
Find all solutions with 0∘≤θ≤180∘0^\circ \leq \theta \leq 180^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecos⁡(θ)=−1\cos(\theta) = -1\newline‾∘\underline{\hspace{2em}}^\circ
Get tutor helpright-arrow

Posted 1 month ago

Question
Kimi's school is 1515 kilometers west of her house and 88 kilometers south of her friend Franklin's house. Every day, Kimi bicycles from her house to her school. After school, she bicycles from her school to Franklin's house. Before dinner, she bicycles home on a bike path that goes straight from Franklin's house to her own house. How far does Kimi bicycle each day?\newline_____\_\_\_\_\_ kilometers
Get tutor helpright-arrow

Posted 1 month ago

Question
Evaluate. Write your answer as an integer or as a decimal rounded to the nearest hundredth.\newlinecos⁡35∘=\cos 35^\circ = __
Get tutor helpright-arrow

Posted 1 month ago

Question
Find all solutions with −90∘≤θ≤90∘-90^\circ \leq \theta \leq 90^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecsc⁡(θ)=−1\csc(\theta) = -1\newline____ ∘\_\_\_\_\,^\circ
Get tutor helpright-arrow

Posted 1 month ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecot⁡30∘=\cot 30^\circ = ______
Get tutor helpright-arrow

Posted 1 month ago

Question
The terminal side of an angle θ\theta in standard position intersects the unit circle at (8485,1385)(\frac{84}{85}, \frac{13}{85}). What is cos⁡(θ)\cos(\theta)?\newlineWrite your answer in simplified, rationalized form.\newline______
Get tutor helpright-arrow

Posted 1 month ago

Question
−90∘<θ<90∘-90^\circ < \theta < 90^\circ. Find the value of θ\theta in degrees.\newlinetan⁡(θ)=0\tan(\theta) = 0\newlineWrite your answer in simplified, rationalized form. Do not round.\newlineθ=\theta = ____∘^\circ\newline
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecsc⁡60∘=\csc 60^\circ = ______
Get tutor helpright-arrow

Posted 1 month ago

Question
θ\theta is an acute angle. Find the value of θ\theta in degrees.\newlinesec⁡(θ)=2\sec(\theta) = \sqrt{2}\newlineθ=\theta = ____°\degree
Get tutor helpright-arrow

Posted 1 month ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecos⁡90∘=\cos 90^\circ = ____
Get tutor helpright-arrow

Posted 2 months ago

View all (117)