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DehaMath Sudent Application
Heme
Use technology to find points and then graph the function
y=2root(3)(x-3)-5, following the instructions below.
done plotting points
Plot at least four points that fit on the axes below. Click a point to delete it.

DehaMath Sudent Application $\newline$ Heme $\newline$ Use technology to find points and then graph the function $y=2 \sqrt[3]{x-3}-5$ , following the instructions below. $\newline$ done plotting points $\newline$ Plot at least four points that fit on the axes below. Click a point to delete it.

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Probability of compound events

Full solution

Q. DehaMath Sudent Application

\newline

Heme

\newline

Use technology to find points and then graph the function

y=2 \sqrt[3]{x-3}-5

, following the instructions below.

\newline

done plotting points

\newline

Plot at least four points that fit on the axes below. Click a point to delete it.

Choose $x=3$ : To graph the function $y=2\sqrt{3}(x-3)-5$ , we need to choose values for $x$ , plug them into the function, and calculate the corresponding $y$ values. We will plot at least $4$ points.
Choose $x=4$ : Let's choose $x=3$ as our first value since it will simplify the square root term. Plugging $x=3$ into the function gives us $y=2\sqrt{3}(3-3)-5$ , which simplifies to $y=2\sqrt{3}(0)-5$ . Since the square root of $0$ is $0$ , this further simplifies to $y=0-5$ , which is $y=-5$ .
Point: $(3, -5)$
Choose $x=6$ : Now let's choose $x=4$ . Plugging $x=4$ into the function gives us $y=2\sqrt{3}(4-3)-5$ , which simplifies to $y=2\sqrt{3}(1)-5$ . Since the square root of $1$ is $1$ , this further simplifies to $y=2\cdot 1-5$ , which is $y=2-5$ , which is $y=-3$ .
Point: $x=4$ $0$
Choose $x=9$ : Next, let's choose $x=6$ . Plugging $x=6$ into the function gives us $y=2\sqrt{3}(6-3)-5$ , which simplifies to $y=2\sqrt{3}(3)-5$ . The square root of $3$ is approximately $1.732$ , so this further simplifies to $y=2\times 1.732-5$ , which is approximately $y=3.464-5$ , which is approximately $y=-1.536$ . $\newline$ Point: $(6, -1.536)$
Choose $x=9$ : Next, let's choose $x=6$ . Plugging $x=6$ into the function gives us $y=2\sqrt{3}(6-3)-5$ , which simplifies to $y=2\sqrt{3}(3)-5$ . The square root of $3$ is approximately $1.732$ , so this further simplifies to $y=2\times1.732-5$ , which is approximately $y=3.464-5$ , which is approximately $y=-1.536$ . $\newline$ Point: $x=6$ $0$ Finally, let's choose $x=9$ . Plugging $x=9$ into the function gives us $x=6$ $3$ , which simplifies to $x=6$ $4$ . The square root of $x=6$ $5$ is approximately $x=6$ $6$ , so this further simplifies to $x=6$ $7$ , which is approximately $x=6$ $8$ , which is approximately $x=6$ $9$ . $\newline$ Point: $x=6$ $0$

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