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Date
Name
Find the perimeter and area of the shaded section. Fill in each 
◻.
(1)
Perimeter of the shaded section

= Circumference of the 
16cm circle + Circumference of the 
8cm circle

=(◻×3.14)+(◻×3.14)
[
]

◻ 
+ 
◻ 
= 
◻ 
cm
Area of the shaded section

= Area of the 
16cm circle - Area of the 
8cm circle

{:[=(◻×◻×3.14)-(◻×◻×3.14)],[=◻-◻cm^(2)]:}
3

Date\newlineName\newlineFind the perimeter and area of the shaded section. Fill in each \square .\newline(11)\newlinePerimeter of the shaded section\newline= = Circumference of the 16 cm 16 \mathrm{~cm} circle + Circumference of the 8 cm 8 \mathrm{~cm} circle\newline=(×3.14)+(×3.14) =(\square \times 3.14)+(\square \times 3.14) \newline= = \newline \square + + \square = = \square cm \mathrm{cm} \newlineArea of the shaded section\newline= = Area of the 16 cm 16 \mathrm{~cm} circle - Area of the 8 cm 8 \mathrm{~cm} circle\newline=(××3.14)(××3.14)=cm2 \begin{array}{l} =(\square \times \square \times 3.14)-(\square \times \square \times 3.14) \\ =\square-\square \mathrm{cm}^{2} \end{array} \newline33

Full solution

Q. Date\newlineName\newlineFind the perimeter and area of the shaded section. Fill in each \square .\newline(11)\newlinePerimeter of the shaded section\newline= = Circumference of the 16 cm 16 \mathrm{~cm} circle + Circumference of the 8 cm 8 \mathrm{~cm} circle\newline=(×3.14)+(×3.14) =(\square \times 3.14)+(\square \times 3.14) \newline= = \newline \square + + \square = = \square cm \mathrm{cm} \newlineArea of the shaded section\newline= = Area of the 16 cm 16 \mathrm{~cm} circle - Area of the 8 cm 8 \mathrm{~cm} circle\newline=(××3.14)(××3.14)=cm2 \begin{array}{l} =(\square \times \square \times 3.14)-(\square \times \square \times 3.14) \\ =\square-\square \mathrm{cm}^{2} \end{array} \newline33
  1. Calculate Circumference: Perimeter of the shaded section = Circumference of the 16cm16\,\text{cm} circle + Circumference of the 8cm8\,\text{cm} circle. Circumference of a circle = 2πradius2 \cdot \pi \cdot \text{radius}. For the 16cm16\,\text{cm} circle, radius = 16cm16\,\text{cm}, so circumference = 2π162 \cdot \pi \cdot 16. For the 8cm8\,\text{cm} circle, radius = 8cm8\,\text{cm}, so circumference = 2π82 \cdot \pi \cdot 8.
  2. Calculate Perimeter: Calculate the circumference of the 16cm16\,\text{cm} circle: 2×3.14×16=100.48cm2 \times 3.14 \times 16 = 100.48\,\text{cm}. Calculate the circumference of the 8cm8\,\text{cm} circle: 2×3.14×8=50.24cm2 \times 3.14 \times 8 = 50.24\,\text{cm}.
  3. Calculate Area: Add the circumferences to find the perimeter: 100.48cm+50.24cm=150.72cm100.48\,\text{cm} + 50.24\,\text{cm} = 150.72\,\text{cm}.
  4. Subtract Areas: Area of the shaded section = Area of the 16cm16\,\text{cm} circle - Area of the 8cm8\,\text{cm} circle.\newlineArea of a circle = π×radius2\pi \times \text{radius}^2.\newlineFor the 16cm16\,\text{cm} circle, radius = 16cm16\,\text{cm}, so area = π×162\pi \times 16^2.\newlineFor the 8cm8\,\text{cm} circle, radius = 8cm8\,\text{cm}, so area = π×82\pi \times 8^2.
  5. Subtract Areas: Area of the shaded section = Area of the 16cm16\,\text{cm} circle - Area of the 8cm8\,\text{cm} circle.\newlineArea of a circle = π×radius2\pi \times \text{radius}^2.\newlineFor the 16cm16\,\text{cm} circle, radius = 16cm16\,\text{cm}, so area = π×162\pi \times 16^2.\newlineFor the 8cm8\,\text{cm} circle, radius = 8cm8\,\text{cm}, so area = π×82\pi \times 8^2.Calculate the area of the 16cm16\,\text{cm} circle: 8cm8\,\text{cm}00.\newlineCalculate the area of the 8cm8\,\text{cm} circle: 8cm8\,\text{cm}22.
  6. Subtract Areas: Area of the shaded section = Area of the 16cm16\,\text{cm} circle - Area of the 8cm8\,\text{cm} circle.\newlineArea of a circle = π×radius2\pi \times \text{radius}^2.\newlineFor the 16cm16\,\text{cm} circle, radius = 16cm16\,\text{cm}, so area = π×162\pi \times 16^2.\newlineFor the 8cm8\,\text{cm} circle, radius = 8cm8\,\text{cm}, so area = π×82\pi \times 8^2.Calculate the area of the 16cm16\,\text{cm} circle: 8cm8\,\text{cm}00.\newlineCalculate the area of the 8cm8\,\text{cm} circle: 8cm8\,\text{cm}22.Subtract the area of the 8cm8\,\text{cm} circle from the area of the 16cm16\,\text{cm} circle: 8cm8\,\text{cm}55.

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