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Darrell is playing hide-and-seek with Victor and Scarlett. Victor is hiding 16meters16\,\text{meters} south of Darrell, and Scarlett is hiding 12meters12\,\text{meters} east of Victor. How far apart are Darrell and Scarlett?\newline_____\_\_\_\_\_ meters

Full solution

Q. Darrell is playing hide-and-seek with Victor and Scarlett. Victor is hiding 16meters16\,\text{meters} south of Darrell, and Scarlett is hiding 12meters12\,\text{meters} east of Victor. How far apart are Darrell and Scarlett?\newline_____\_\_\_\_\_ meters
  1. Identify Positions: Identify the positions of Victor and Scarlett relative to Darrell. Victor is 1616 meters south of Darrell, and Scarlett is 1212 meters east of Victor.
  2. Visualize as Triangle: Visualize the scenario as a right triangle where Darrell and Scarlett form the hypotenuse. The distance from Darrell to Victor is one leg (1616 meters), and the distance from Victor to Scarlett is the other leg (1212 meters).
  3. Apply Pythagorean Theorem: Apply the Pythagorean Theorem to find the distance between Darrell and Scarlett. Let d be the distance between Darrell and Scarlett.\newlined2=162+122 d^2 = 16^2 + 12^2
  4. Calculate Squares: Calculate the squares of the legs.\newline162=256 16^2 = 256 \newline122=144 12^2 = 144 \newlined2=256+144 d^2 = 256 + 144
  5. Add Squares: Add the squares of the legs.\newlined2=400 d^2 = 400
  6. Find Distance: Find the square root of 400400 to get the distance d.\newlined=400 d = \sqrt{400} \newlined=20 d = 20 meters

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