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d(1)=8d(1)=8 d(n)=d(n1)×(5)d(n)=d(n-1)\times(-5) \newlineWhat is the third term?

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Q. d(1)=8d(1)=8 d(n)=d(n1)×(5)d(n)=d(n-1)\times(-5) \newlineWhat is the third term?
  1. Find Second Term: First, let's find the second term using the recursive formula d(n)=d(n1)×(5)d(n) = d(n-1) \times (-5).d(2)=d(21)×(5)=d(1)×(5)=8×(5)=40d(2) = d(2-1) \times (-5) = d(1) \times (-5) = 8 \times (-5) = -40.
  2. Find Third Term: Now, let's find the third term using the second term we just found. d(3)=d(31)×(5)=d(2)×(5)=40×(5)=200d(3) = d(3-1) \times (-5) = d(2) \times (-5) = -40 \times (-5) = 200.

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