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ctice Quiz Final [CA]
possible
A waitress sold 10 ribeye steak dinners and 26 grilled salmon dinners, totaling
$585.15 on a particular day. Another day she sold 25 ribeye steak dinners and 13 grilled salmon dinners, totaling
$580.82. How much did each type of dinner cost?

◻ and the cost of salmon dinners is
$
◻ .
The cost of ribeye steak dinners is
$
◻ (Simplify your answer. Round to the nearest hundredth as needed.)

ctice Quiz Final [CA] $\newline$ possible $\newline$ A waitress sold $10$ ribeye steak dinners and $26$ grilled salmon dinners, totaling $\$ 585.15$ on a particular day. Another day she sold $25$ ribeye steak dinners and $13$ grilled salmon dinners, totaling $\$ 580.82$ . How much did each type of dinner cost? $\newline$ $\square$ and the cost of salmon dinners is $\$$ $\square$ . $\newline$ The cost of ribeye steak dinners is $\$$ $\square$ (Simplify your answer. Round to the nearest hundredth as needed.)

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Exponential growth and decay: word problems

Full solution

Q. ctice Quiz Final [CA]

\newline

possible

\newline

A waitress sold

10

ribeye steak dinners and

26

grilled salmon dinners, totaling

\$ 585.15

on a particular day. Another day she sold

25

ribeye steak dinners and

13

grilled salmon dinners, totaling

\$ 580.82

. How much did each type of dinner cost?

\newline

\square

and the cost of salmon dinners is

\$

\square

.

\newline

The cost of ribeye steak dinners is

\$

\square

(Simplify your answer. Round to the nearest hundredth as needed.)

Define Variables: Let's call the cost of a ribeye steak dinner $R$ and the cost of a grilled salmon dinner $S$ . We have two equations based on the given information: $10R + 26S = 585.15$ ... ( $1$ ) $25R + 13S = 580.82$ ... ( $2$ )
Multiply Equation: Now, let's multiply equation $(1)$ by $2.5$ to match the number of ribeye steak dinners in equation $(2)$ : $\newline$ $25R + 65S = 1462.875 \ldots (3)$
Subtract Equations: Next, we subtract equation ( $2$ ) from equation ( $3$ ) to eliminate $R$ : $\newline$ $(25R + 65S) - (25R + 13S) = 1462.875 - 580.82$ $\newline$ $40S = 882.055$
Solve for S: Now, we solve for S: $\newline$ $S = \frac{882.055}{40}$ $\newline$ $S = 22.051375$
Round S Value: Round $S$ to the nearest hundredth: $S \approx 22.05$
Substitute $S$ into Equation: Now we substitute the value of $S$ back into equation ( $1$ ) to find $R$ : $10R + 26(22.05) = 585.15$ $10R + 573.3 = 585.15$
Solve for R: Subtract $573.3$ from both sides to solve for R: $\newline$ $10R = 585.15 - 573.3$ $\newline$ $10R = 11.85$
Divide to Find R: Finally, we divide by $10$ to find $R$ : $\newline$ $R = 11.85 / 10$ $\newline$ $R = 1.185$

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