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Crammer rule:-
Question No L..

{:[x_(1)+x_(2)+x_(3)=2],[2x_(1)-x_(2)+x_(3)=9],[2x_(1)+3x_(2)+4x_(3)=4]:}

Crammer rule:-\newlineQuestion No L..\newlinex1+x2+x3=22x1x2+x3=92x1+3x2+4x3=4 \begin{aligned} x_{1}+x_{2}+x_{3} & =2 \\ 2 x_{1}-x_{2}+x_{3} & =9 \\ 2 x_{1}+3 x_{2}+4 x_{3} & =4 \end{aligned}

Full solution

Q. Crammer rule:-\newlineQuestion No L..\newlinex1+x2+x3=22x1x2+x3=92x1+3x2+4x3=4 \begin{aligned} x_{1}+x_{2}+x_{3} & =2 \\ 2 x_{1}-x_{2}+x_{3} & =9 \\ 2 x_{1}+3 x_{2}+4 x_{3} & =4 \end{aligned}
  1. Substitute point into first equation: First, let's substitute the point (1,1,1)(1,1,1) into the first equation: x1+x2+x3=2x_1 + x_2 + x_3 = 2. Substituting x1=1x_1=1, x2=1x_2=1, and x3=1x_3=1, we get 1+1+1=31 + 1 + 1 = 3.

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