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cosxcos2x=cos3x\cos x\cos 2x = \cos 3x

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Q. cosxcos2x=cos3x\cos x\cos 2x = \cos 3x
  1. Apply Cosine Angle Addition Formula: Use the cosine angle addition formula, cos(A+B)=cos(A)cos(B)sin(A)sin(B)\cos(A + B) = \cos(A)\cos(B) - \sin(A)\sin(B), to express cos(3x)\cos(3x) in terms of cos(x)\cos(x) and cos(2x)\cos(2x).\newlinecos(3x)=cos(2x+x)\cos(3x) = \cos(2x + x) \newline=cos(2x)cos(x)sin(2x)sin(x)= \cos(2x)\cos(x) - \sin(2x)\sin(x)
  2. Express cos(3x)\cos(3x) in terms: Compare the given equation cos(x)cos(2x)=cos(3x)\cos(x)\cos(2x) = \cos(3x) with the expanded form.\newlinecos(x)cos(2x)=cos(2x)cos(x)sin(2x)sin(x)\cos(x)\cos(2x) = \cos(2x)\cos(x) - \sin(2x)\sin(x)

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