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corresponding heights.
proportional
to
the
Practice set 1.1
Base of a triangle is 9 and height is 5 . Base of another triangle is 10 and is 6 . Find the ratio of areas of these triangles.

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corresponding heights.\newlineproportional\newlineto\newlinethe\newlinePractice set 11.11\newlineBase of a triangle is 99 and height is 55 . Base of another triangle is 1010 and is 66 . Find the ratio of areas of these triangles.\newline \square :

Full solution

Q. corresponding heights.\newlineproportional\newlineto\newlinethe\newlinePractice set 11.11\newlineBase of a triangle is 99 and height is 55 . Base of another triangle is 1010 and is 66 . Find the ratio of areas of these triangles.\newline \square :
  1. Calculate Second Triangle Area: Now, let's find the area of the second triangle using the same formula.\newlineArea of the second triangle = (10×6)/2(10 \times 6) / 2.\newlineArea of the second triangle = 60/260 / 2.\newlineArea of the second triangle = 3030.
  2. Find Ratio of Areas: Finally, we find the ratio of the areas of the two triangles.\newlineRatio of areas = Area of first triangle / Area of second triangle.\newlineRatio of areas = 22.530.\frac{22.5}{30}.
  3. Simplify Ratio: Simplify the ratio by dividing both the numerator and the denominator by the greatest common divisor, which is 7.57.5 in this case.\newlineRatio of areas = (22.5/7.5)/(30/7.5)(22.5 / 7.5) / (30 / 7.5).\newlineRatio of areas = 3/43 / 4.

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