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Consider the equation 14*10^(0.5 w)=100.
Solve the equation for w. Express the solution as a logarithm in base- 10 .
w=◻
Approximate the value of w. Round your answer to the nearest thousandth.
w~~◻

Consider the equation 14100.5w=100 14 \cdot 10^{0.5 w}=100 .\newlineSolve the equation for w w . Express the solution as a logarithm in base- 1010 .\newlinew=w = \square \newlineApproximate the value of w w . Round your answer to the nearest thousandth.\newlineww \approx \square

Full solution

Q. Consider the equation 14100.5w=100 14 \cdot 10^{0.5 w}=100 .\newlineSolve the equation for w w . Express the solution as a logarithm in base- 1010 .\newlinew=w = \square \newlineApproximate the value of w w . Round your answer to the nearest thousandth.\newlineww \approx \square
  1. Take Logarithm: Now, we will take the logarithm of both sides of the equation to remove the exponent on the left side. We will use the base10-10 logarithm since we want to express the solution as a logarithm in base10-10.\newlinelog(100.5w)=log(7.14285714)\log(10^{0.5 w}) = \log(7.14285714\ldots)\newline0.5wlog(10)=log(7.14285714)0.5 w \cdot \log(10) = \log(7.14285714\ldots)\newlineSince log(10)\log(10) is 11, this simplifies to:\newline0.5w=log(7.14285714)0.5 w = \log(7.14285714\ldots)
  2. Divide and Solve: Next, we divide both sides of the equation by 0.50.5 to solve for ww.\newline0.5w/0.5=log(7.14285714...)/0.50.5 w / 0.5 = \log(7.14285714...) / 0.5\newlinew=2×log(7.14285714...)w = 2 \times \log(7.14285714...)
  3. Calculate Approximate Value: Now we can use a calculator to find the approximate value of ww. We will round the answer to the nearest thousandth.\newlinew2×log(7.14285714...)w \approx 2 \times \log(7.14285714...)\newlinew2×0.853871964w \approx 2 \times 0.853871964\newlinew1.707743928w \approx 1.707743928\newlineRounded to the nearest thousandth:\newlinew1.708w \approx 1.708

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