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Condense the logarithm

g log a+log d
Answer: 
log(◻)

Condense the logarithm\newlinegloga+logd g \log a+\log d \newlineAnswer: log() \log (\square)

Full solution

Q. Condense the logarithm\newlinegloga+logd g \log a+\log d \newlineAnswer: log() \log (\square)
  1. Question Prompt: Question prompt: Condense the expression gloga+logdg \log a + \log d into a single logarithm.
  2. Combine Logarithms: Apply the logarithm property that allows us to combine two logarithms with the same base that are being added into a single logarithm by multiplying their arguments.\newlineThe property is logb(m)+logb(n)=logb(mn)\log_b(m) + \log_b(n) = \log_b(m*n), where bb is the base of the logarithms.
  3. Rewrite Coefficient: Use the property from Step 11 to combine gloga+logdg \log a + \log d. Since gg is a coefficient of loga\log a, we can rewrite it as logag\log a^g using the property that glogb(m)=logb(mg)g\log_b(m) = \log_b(m^g). So, gloga+logd=logag+logdg \log a + \log d = \log a^g + \log d.
  4. Final Simplification: Now apply the property from Step 11 to the expression logag+logd\log a^g + \log d. This gives us log(agd)\log(a^g \cdot d).

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