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Condense the logarithm

7log a-x log d
Answer: 
log(◻)

Condense the logarithm\newline7logaxlogd 7 \log a-x \log d \newlineAnswer: log() \log (\square)

Full solution

Q. Condense the logarithm\newline7logaxlogd 7 \log a-x \log d \newlineAnswer: log() \log (\square)
  1. Rewrite using power rule: We are given the expression 7log(a)xlog(d)7\log(a) - x\log(d) and we need to condense it into a single logarithm.\newlineAccording to the properties of logarithms, specifically the power rule which states that nlogb(m)=logb(mn)n\log_b(m) = \log_b(m^n), we can rewrite each term as follows:\newline7log(a)7\log(a) becomes log(a7)\log(a^7) and xlog(d)x\log(d) becomes log(dx)\log(d^x).
  2. Combine using quotient rule: Now we have log(a7)log(dx)\log(a^7) - \log(d^x). According to the quotient rule of logarithms, which states that logb(m)logb(n)=logb(mn)\log_b(m) - \log_b(n) = \log_b\left(\frac{m}{n}\right), we can combine these two logarithms into a single logarithm with a quotient inside.\newlineSo, log(a7)log(dx)\log(a^7) - \log(d^x) becomes log(a7dx)\log\left(\frac{a^7}{d^x}\right).
  3. Final condensed expression: We have successfully condensed the original expression into a single logarithm. The final answer is log(a7dx)\log\left(\frac{a^7}{d^x}\right).

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