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Condense the logarithm

3log a+log k
Answer: 
log(◻)

Condense the logarithm\newline3loga+logk 3 \log a+\log k \newlineAnswer: log() \log (\square)

Full solution

Q. Condense the logarithm\newline3loga+logk 3 \log a+\log k \newlineAnswer: log() \log (\square)
  1. Apply Logarithm Power Rule: We are given the logarithmic expression 3loga+logk3\log a + \log k and we need to condense it into a single logarithm.\newlineAccording to the logarithm power rule, which states that nlogb(x)=logb(xn)n \cdot \log_b(x) = \log_b(x^n), we can rewrite 3loga3\log a as loga3\log a^3.
  2. Apply Logarithm Product Rule: Now we have loga3+logk\log a^3 + \log k. According to the logarithm product rule, which states that logb(x)+logb(y)=logb(xy)\log_b(x) + \log_b(y) = \log_b(xy), we can combine these two logarithms into one.\newlineSo, loga3+logk\log a^3 + \log k becomes log(a3k)\log(a^3 \cdot k).
  3. Final Condensed Form: We have successfully condensed the logarithm into a single expression without making any mathematical errors.\newlineThe final condensed form is log(a3k)\log(a^3 \cdot k).

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