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Complete the recursive formula of the geometric sequence

{:[16","3.2","0.64","0.128","dots.],[a(1)=],[a(n)=a(n-1)*]:}

Complete the recursive formula of the geometric sequence\newline16,3.2,0.64,0.128, 16,3.2,0.64,0.128, \ldots \text {. } \newlinea(1)= a(1)= \square \newlinea(n)=a(n1) a(n)=a(n-1) \cdot \square

Full solution

Q. Complete the recursive formula of the geometric sequence\newline16,3.2,0.64,0.128, 16,3.2,0.64,0.128, \ldots \text {. } \newlinea(1)= a(1)= \square \newlinea(n)=a(n1) a(n)=a(n-1) \cdot \square
  1. Given Sequence: We are given the geometric sequence: 16,3.2,0.64,0.128,16, 3.2, 0.64, 0.128, \ldots\newlineTo find the recursive formula, we need to determine the common ratio by dividing any term by the previous term.\newlineLet's divide the second term by the first term to find the common ratio (r)(r).\newliner=3.216r = \frac{3.2}{16}
  2. Find Common Ratio: Now, let's perform the calculation to find the value of rr.r=3.216=0.2r = \frac{3.2}{16} = 0.2This means that each term is multiplied by 0.20.2 to get the next term.
  3. Calculate Common Ratio: We are also given the first term of the sequence, which is a(1)=16a(1) = 16. Now we can write the recursive formula for the sequence using the common ratio and the first term. The recursive formula is: a(n)=a(n1)×ra(n) = a(n-1) \times r Substitute the value of rr into the formula. a(n)=a(n1)×0.2a(n) = a(n-1) \times 0.2

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