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Complete the equation of the line through
(3,-8) and
(6,-4).
Use exact numbers.

y=

◻

Complete the equation of the line through $(3,-8)$ and $(6,-4)$ . $\newline$ Use exact numbers. $\newline$ $y=$ $\newline$ $\square$

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Find the magnitude of a three-dimensional vector

Full solution

Q. Complete the equation of the line through

(3,-8)

and

(6,-4)

.

\newline

Use exact numbers.

\newline

y=

\newline

\square

Use Point-Slope Form: Now, use the point-slope form of the equation of a line: $y - y_1 = m(x - x_1)$ . Choose one of the points, say $(3, -8)$ , and plug in the values along with the slope. $y - (-8) = \frac{4}{3}(x - 3)$ $y + 8 = \frac{4}{3}x - 4$
Plug in Values: Subtract $8$ from both sides to get $y$ by itself. $\newline$ $y = \left(\frac{4}{3}\right)x - 4 - 8$ $\newline$ $y = \left(\frac{4}{3}\right)x - 12$

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