Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Compare the numbers. Pick the correct sign. $\newline$ $-3 \,?\, -6$ $\newline$ $\newline$ You can use the number line to help. $\newline$ $\newline$ Choices: $\newline$ (A) $>$ $\newline$ (B) $<$ $\newline$ (C) $=$

View step-by-step help

View step-by-step help

Evaluate powers with negative or zero exponents

Full solution

Q. Compare the numbers. Pick the correct sign.

\newline

-3 \,?\, -6

\newline

\newline

You can use the number line to help.

\newline

\newline

Choices:

\newline

(A)

>

\newline

(B)

<

\newline

(C)

=

Check Number Line: Check the numbers on a number line; $-3$ is to the right of $-6$ .
Compare Numbers: Since numbers to the right are greater on the number line, $-3$ is greater than $-6$ .
Choose Correct Sign: Choose the correct sign that shows $-3$ is greater than $-6$ .

More problems from Evaluate powers with negative or zero exponents

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 3 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 3 months ago

Question

x^2 = 4

Posted 2 months ago

Question

x^2 = 9

Posted 4 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 4 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 4 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 4 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 16 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 2 months ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 2 months ago