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Circle 
O shown below has a radius of 11 inches. To the nearest tenth of an inch, determine the length of the arc, 
x, subtended by an angle of 
145^(@).
Answer: inches

Circle O O shown below has a radius of 1111 inches. To the nearest tenth of an inch, determine the length of the arc, x x , subtended by an angle of 145 145^{\circ} .\newlineAnswer: \square inches

Full solution

Q. Circle O O shown below has a radius of 1111 inches. To the nearest tenth of an inch, determine the length of the arc, x x , subtended by an angle of 145 145^{\circ} .\newlineAnswer: \square inches
  1. Identify formula: Identify the formula to calculate the length of an arc.\newlineThe length of an arc LL in a circle is given by the formula L=(θ/360)×2πrL = (\theta/360) \times 2\pi r, where θ\theta is the central angle in degrees and rr is the radius of the circle.
  2. Plug values: Plug in the given values into the formula.\newlineHere, θ=145\theta = 145 degrees and r=11r = 11 inches. Using the approximation π3.14\pi \approx 3.14, we can calculate the length of the arc.\newlineL=(145360)×2×3.14×11L = (\frac{145}{360}) \times 2 \times 3.14 \times 11
  3. Calculate arc length: Calculate the length of the arc.\newlineFirst, calculate the fraction of the circle that the arc covers by dividing the angle by 360360 degrees.\newline1453600.4028\frac{145}{360} \approx 0.4028 (rounded to four decimal places for precision in intermediate steps)\newlineNow, multiply this fraction by the circumference of the entire circle (2πr)(2 \cdot \pi \cdot r).\newlineL0.402823.1411L \approx 0.4028 \cdot 2 \cdot 3.14 \cdot 11
  4. Perform multiplication: Perform the multiplication to find the length of the arc.\newlineL0.4028×2×3.14×11L \approx 0.4028 \times 2 \times 3.14 \times 11\newlineL0.4028×69.08L \approx 0.4028 \times 69.08 (since 2×3.14×11=69.082 \times 3.14 \times 11 = 69.08)\newlineL27.8264L \approx 27.8264 inches
  5. Round result: Round the result to the nearest tenth of an inch as the problem asks.\newlineL27.8L \approx 27.8 inches (rounded to the nearest tenth)

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