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Check all symmetries that apply.
(a) 
28x^(2)+32y^(2)=65
(b) 
y=-7x
Symmetry:

x-axis

y-axis
origin
none of the above
Symmetry:

x-axis

y-axis
origin
none of the above

Check all symmetries that apply.\newline(a) 28x2+32y2=65 28 x^{2}+32 y^{2}=65 \newline(b) y=7x y=-7 x \newlineSymmetry:\newlinex x -axis\newliney y -axis\newlineorigin\newlinenone of the above\newlineSymmetry:\newlinex x -axis\newliney y -axis\newlineorigin\newlinenone of the above

Full solution

Q. Check all symmetries that apply.\newline(a) 28x2+32y2=65 28 x^{2}+32 y^{2}=65 \newline(b) y=7x y=-7 x \newlineSymmetry:\newlinex x -axis\newliney y -axis\newlineorigin\newlinenone of the above\newlineSymmetry:\newlinex x -axis\newliney y -axis\newlineorigin\newlinenone of the above
  1. Replace yy with y-y: To determine if the equation (a) 28x2+32y2=6528x^2 + 32y^2 = 65 has x-axis symmetry, replace yy with y-y and see if the equation remains unchanged.\newlineCalculation: 28x2+32(y)2=28x2+32y2=6528x^2 + 32(-y)^2 = 28x^2 + 32y^2 = 65
  2. X-axis symmetry confirmed: Since the equation is unchanged when yy is replaced with y-y, the equation (a)(a) has xx-axis symmetry.
  3. Replace xx with x-x: To determine if the equation (a) has y-axis symmetry, replace xx with x-x and see if the equation remains unchanged.\newlineCalculation: 28(x)2+32y2=28x2+32y2=6528(-x)^2 + 32y^2 = 28x^2 + 32y^2 = 65
  4. Y-axis symmetry confirmed: Since the equation is unchanged when xx is replaced with x-x, the equation (a) has yy-axis symmetry.
  5. Replace xx and yy with negatives: To determine if the equation (a) has origin symmetry, replace xx with x-x and yy with y-y and see if the equation remains unchanged.\newlineCalculation: 28(x)2+32(y)2=28x2+32y2=6528(-x)^2 + 32(-y)^2 = 28x^2 + 32y^2 = 65
  6. Origin symmetry confirmed: Since the equation is unchanged when both xx and yy are replaced with their negatives, the equation (a)(a) has origin symmetry.
  7. Replace yy with y-y: To determine if the equation (b) y=7xy = -7x has x-axis symmetry, replace yy with y-y and see if the equation remains unchanged.\newlineCalculation: y=7x-y = -7x
  8. No x-axis symmetry: Since the equation is not unchanged (it becomes y=7x-y = -7x, which is not equivalent to y=7xy = -7x), the equation (b)(b) does not have x-axis symmetry.
  9. Replace xx with x-x: To determine if the equation (b) has y-axis symmetry, replace xx with x-x and see if the equation remains unchanged.\newlineCalculation: y=7(x)=7xy = -7(-x) = 7x
  10. No y-axis symmetry: Since the equation is not unchanged (it becomes y=7xy = 7x, which is not equivalent to y=7xy = -7x), the equation (b)(b) does not have y-axis symmetry.
  11. Replace xx and yy with negatives: To determine if the equation (b) has origin symmetry, replace xx with x-x and yy with y-y and see if the equation remains unchanged.\newlineCalculation: y=7(x)=7x-y = -7(-x) = 7x
  12. Origin symmetry confirmed: Since the equation is unchanged when both xx and yy are replaced with their negatives (it becomes y=7x-y = 7x, which is equivalent to y=7xy = -7x after multiplying both sides by 1-1), the equation (b) has origin symmetry.

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