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Ch. 3 -Acute Triangle Trigonometry
25 Mar 2024
nearest tenth of a metre?
How far is the point on the ground from the base of the building, to How tall is the crane?

x=27

$5$ . $\newline$ Ch. $3$ -Acute Triangle Trigonometry $\newline$ $25$ Mar $2024$ $\newline$ nearest tenth of a metre? $\newline$ How far is the point on the ground from the base of the building, to How tall is the crane? $\newline$ $x=27$

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Pythagorean theorem

Full solution

Q.

5

.

\newline

Ch.

3

-Acute Triangle Trigonometry

\newline

25

Mar

2024

\newline

nearest tenth of a metre?

\newline

How far is the point on the ground from the base of the building, to How tall is the crane?

\newline

x=27

Right Triangle Description: We have a right triangle with the crane's height as one leg ( $27$ meters) and the distance from the point on the ground to the base of the building as the other leg. We need to find the hypotenuse.
Pythagorean Theorem Application: Let's call the distance from the point on the ground to the base of the building ' $d$ '. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse ( $c$ ) is equal to the sum of the squares of the other two sides ( $a$ and $b$ ). So, $c^2 = a^2 + b^2$ .
Missing Information Issue: We know the height of the crane $a$ is $27$ meters, but we don't have the hypotenuse $c$ or the distance $d$ . The problem seems to be missing information, as we only have one side of the triangle. We can't solve for the hypotenuse without the length of the other leg or the hypotenuse itself.

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