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Carbon-14 has a half-life of 5730 years. After 17,190 years, only 
3g remains. What was the mass of the original sample?

1111. Carbon14-14 has a half-life of 57305730 years. After 1717,190190 years, only 3g 3 g remains. What was the mass of the original sample?

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Q. 1111. Carbon14-14 has a half-life of 57305730 years. After 1717,190190 years, only 3g 3 g remains. What was the mass of the original sample?
  1. Determine Initial Mass: We need to determine the initial mass of a Carbon-\newline1414 sample that has decayed to 3g3\,\text{g} after 17,19017,190 years. The half-life of Carbon-1414 is 57305730 years. We can use the formula for exponential decay to find the original mass.
  2. Calculate Number of Half-Lives: First, let's determine how many half-lives have passed in 17,19017,190 years. We do this by dividing the total time by the half-life of Carbon14-14.\newlineNumber of half-lives = Total time / Half-life = 17,19017,190 years / 57305730 years
  3. Calculate Remaining Mass: Calculating the number of half-lives:\newlineNumber of half-lives = 17,1905,730=3\frac{17,190}{5,730} = 3\newlineThis means that the Carbon14-14 sample has gone through 33 half-lives.
  4. Calculate Initial Mass: Now, we can use the fact that after each half-life, the mass of the radioactive substance is halved. After 33 half-lives, the mass would be halved 33 times.\newlineInitial mass = Remaining mass ×(2Number of half-lives)\times (2^{\text{Number of half-lives}})
  5. Final Calculation: Calculating the initial mass:\newlineInitial mass = 3g×(23)=3g×83\text{g} \times (2^3) = 3\text{g} \times 8
  6. Final Calculation: Calculating the initial mass:\newlineInitial mass = 3g×(23)=3g×83g \times (2^3) = 3g \times 8Final calculation of the initial mass:\newlineInitial mass = 3g×8=24g3g \times 8 = 24g\newlineThe original mass of the Carbon14-14 sample was 2424 grams.

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