c. Find the IQR. $\newline$ Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, and the length is $5$ feet more than twice the width. The perimeter of the lawn is $250$ feet. $\newline$ a. Use the $5$ -D Process to find the dimensions of the lawn. $\newline$ b. Use the dimensions you calculated in part (a) to find the area of the lawn. $\newline$ Evaluate the inequality below for the following listed values of $x$ . Decide if the value makes the statement true or false. Show your work. $\newline$ $\begin{array}{lll} 3 x-3 \geq 2 x+3 \\ x=-3 & \text { b. } x=9.5 \quad \text { c. } \end{array}$ $\newline$ b. $x=9.5$ $\newline$ c. $x=6$ $\newline$ d. $x=10 \frac{1}{2}$ $\newline$ r. Takaya can eat three slices of pizza in five minutes. If he continues to ea the same rate, how long will it take him to eat the whole pizza, which has

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Math Problems

Grade 7

One-step inequalities: word problems

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Q. c. Find the IQR.

\newline

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, and the length is

5

feet more than twice the width. The perimeter of the lawn is

250

feet.

\newline

a. Use the

5

-D Process to find the dimensions of the lawn.

\newline

b. Use the dimensions you calculated in part (a) to find the area of the lawn.

\newline

Evaluate the inequality below for the following listed values of

x

. Decide if the value makes the statement true or false. Show your work.

\newline

\begin{array}{lll} 3 x-3 \geq 2 x+3 \\ x=-3 & \text { b. } x=9.5 \quad \text { c. } \end{array}

\newline

x=9.5

\newline

x=6

\newline

x=10 \frac{1}{2}

\newline

r. Takaya can eat three slices of pizza in five minutes. If he continues to ea the same rate, how long will it take him to eat the whole pizza, which has

Define Width and Length: Let's call the width of the lawn $w$ feet. Then the length is $2w + 5$ feet.
Perimeter Calculation: The perimeter $P$ of a rectangle is given by $P = 2(\text{length} + \text{width})$ . We know $P = 250$ feet.
Solving for Width: So, $250 = 2((2w + 5) + w)$ . Let's solve for ' $w$ '.
Substitute Values: $250 = 2(3w + 5)$
Isolate Width Term: Divide both sides by $2$ to isolate the term with ' $w$ '.
Solve for Width: $125 = 3w + 5$
Final Width Calculation: Subtract $5$ from both sides to solve for $w$ .
Correcting Mistake: $120 = 3w$
Correcting Mistake: $120 = 3w$ Divide both sides by $3$ to find ' $w$ '.
Correcting Mistake: $120 = 3w$ Divide both sides by $3$ to find ' $w$ '. $w = 40$ feet. But we made a mistake here, we should have gotten w = rac{120}{3} = 40 feet.