Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

c.

(5(x+3))/(2)=(x)/(3)

c.\newline5(x+3)2=x3 \frac{5(x+3)}{2}=\frac{x}{3}

Full solution

Q. c.\newline5(x+3)2=x3 \frac{5(x+3)}{2}=\frac{x}{3}
  1. Eliminate Fractions: First, we need to eliminate the fractions by finding a common denominator and multiplying both sides of the equation by that common denominator. The common denominator for 22 and 33 is 66. We will multiply both sides of the equation by 66 to clear the fractions.\newline(6)×5(x+3)2=(6)×x3(6) \times \frac{5(x+3)}{2} = (6) \times \frac{x}{3}
  2. Simplify Equation: Now, we simplify both sides of the equation. On the left side, the 66 and 22 will cancel out, leaving us with 3×(5(x+3))3 \times (5(x+3)). On the right side, the 66 and 33 will cancel out, leaving us with 2x2x.\newline3×(5(x+3))=2x3 \times (5(x+3)) = 2x
  3. Distribute and Combine: Next, we distribute the 33 into the parentheses on the left side of the equation.3×5x+3×3=2x3 \times 5x + 3 \times 3 = 2x15x+9=2x15x + 9 = 2x
  4. Rearrange Terms: Now, we want to get all the xx terms on one side and the constants on the other side. We can do this by subtracting 2x2x from both sides of the equation.15x+92x=2x2x15x + 9 - 2x = 2x - 2x13x+9=013x + 9 = 0
  5. Correct Mistake: We made a mistake in the previous step. We should have subtracted 2x2x from both sides to get the xx terms on one side, but we incorrectly set the right side to 00. Let's correct this.\newline15x+92x=2x2x15x + 9 - 2x = 2x - 2x\newline13x+9=0x13x + 9 = 0x\newline13x+9=013x + 9 = 0

More problems from Add and subtract polynomials