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c.
2^(x)=32

$2^{x}=32$

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Solve equations with variable exponents

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Q.

2^{x}=32

Identify base and target: Identify the base and the target value. $2$ raised to some power equals $32$ . We need to find that power. $\newline$ Base: $2$ $\newline$ Target Value: $32$
Express as power of $2$ : Express $32$ as a power of $2$ . $\newline$ $32$ can be written as $2^5$ because $2 \times 2 \times 2 \times 2 \times 2 = 32$ .
Set equation and solve: Set the equation and solve for $x$ . $\newline$ Since $2^x = 32$ and $32 = 2^5$ , then $2^x = 2^5$ . $\newline$ Therefore, $x = 5$ .

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