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$BODMAS Calculate the following: {:[8+3×2=],[10-6÷2=],[(6+2)÷4=],[(8+1)×(2+3)=],[15-3^(2)+4=],[2+3×(3+2)=],[8+4^(2)÷2=],[20-8-3×(9-7)=],[2^(2)+6^(2)-4^(2)=],[(12-7)×(3^(2)-2^(2))=]:}$

BODMAS $\newline$ Calculate the following: $\newline$ $\begin{array}{l} 8+3 \times 2= \\ 10-6 \div 2= \\ (6+2) \div 4= \\ (8+1) \times(2+3)= \\ 15-3^{2}+4= \\ 2+3 \times(3+2)= \\ 8+4^{2} \div 2= \\ 20-8-3 \times(9-7)= \\ 2^{2}+6^{2}-4^{2}= \\ (12-7) \times\left(3^{2}-2^{2}\right)= \end{array}$

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Grade 7

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Q. BODMAS

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Calculate the following:

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\begin{array}{l} 8+3 \times 2= \\ 10-6 \div 2= \\ (6+2) \div 4= \\ (8+1) \times(2+3)= \\ 15-3^{2}+4= \\ 2+3 \times(3+2)= \\ 8+4^{2} \div 2= \\ 20-8-3 \times(9-7)= \\ 2^{2}+6^{2}-4^{2}= \\ (12-7) \times\left(3^{2}-2^{2}\right)= \end{array}

First expression: Addition and Multiplication: First expression: $8 + 3 \times 2$ . $\newline$ BODMAS says do multiplication before addition. $\newline$ So, $3 \times 2 = 6$ . $\newline$ Now, $8 + 6 = 14$ .
Second expression: Subtraction and Division: Second expression: $10 - 6 \div 2$ . $\newline$ BODMAS says do division before subtraction. $\newline$ So, $6 \div 2 = 3$ . $\newline$ Now, $10 - 3 = 7$ .
Third expression: Brackets and Division: Third expression: $(6 + 2) \div 4$ . BODMAS says do brackets first, then division. So, $6 + 2 = 8$ . Now, $8 \div 4 = 2$ .
Fourth expression: Brackets and Multiplication: Fourth expression: $(8 + 1) \times (2 + 3)$ . $\newline$ BODMAS says do brackets first, then multiplication. $\newline$ So, $8 + 1 = 9$ and $2 + 3 = 5$ . $\newline$ Now, $9 \times 5 = 45$ .
Fifth expression: Exponents and Addition/Subtraction: Fifth expression: $15 - 3^{2} + 4$ . BODMAS says do exponents before addition and subtraction. So, $3^{2} = 9$ . Now, $15 - 9 + 4 = 10$ .