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Beth and her cousin Albert both collect stamps. Beth currently has 8080 stamps in her collection, and she adds 44 more each month. Right now, Albert only has 2020 stamps in his collection, but he adds 1010 more each month.\newlineWhich equation can you use to find mm, the number of months it will take for Albert to have as many stamps as Beth?\newlineChoices:\newline(A) 80+4m=20+10m80 + 4m = 20 + 10m\newline(B) 804m=20+10m80 - 4m = 20 + 10m\newlineHow many months will it take for Albert to have as many stamps as Beth?\newline____ months\newline

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Q. Beth and her cousin Albert both collect stamps. Beth currently has 8080 stamps in her collection, and she adds 44 more each month. Right now, Albert only has 2020 stamps in his collection, but he adds 1010 more each month.\newlineWhich equation can you use to find mm, the number of months it will take for Albert to have as many stamps as Beth?\newlineChoices:\newline(A) 80+4m=20+10m80 + 4m = 20 + 10m\newline(B) 804m=20+10m80 - 4m = 20 + 10m\newlineHow many months will it take for Albert to have as many stamps as Beth?\newline____ months\newline
  1. Question Prompt: Question Prompt: Determine the number of months it will take for Albert to have as many stamps as Beth.
  2. Step 11: Step 11: Set up the equation based on the information given. Beth starts with 8080 stamps and adds 44 each month. Albert starts with 2020 stamps and adds 1010 each month. We need to find when they will have the same number of stamps.
  3. Step 22: Step 22: Write the equation representing each person's stamp collection over time. For Beth: 80+4m80 + 4m, and for Albert: 20+10m20 + 10m. Set them equal to find when they have the same amount: 80+4m=20+10m80 + 4m = 20 + 10m.
  4. Step 33: Step 33: Solve for mm. Subtract 4m4m from both sides to get: 80=20+6m80 = 20 + 6m.
  5. Step 44: Step 44: Subtract 2020 from both sides to isolate the term with mm: 60=6m60 = 6m.
  6. Step 55: Step 55: Divide both sides by 66 to solve for mm: m=10m = 10.

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