Berikut data tinggi bibit pohon (cm) di kampus Poltesa : 81,79,82,83,80,78,80,87,82,82 Hitunglah: 1. simpangan baku 2. varian 3. derajat bebas 4. koefisien keragaman 5. Kuartil 36. desil 67. Persentil 45
Q. Berikut data tinggi bibit pohon (cm) di kampus Poltesa : 81,79,82,83,80,78,80,87,82,82 Hitunglah: 1. simpangan baku 2. varian 3. derajat bebas 4. koefisien keragaman 5. Kuartil 36. desil 67. Persentil 45
Calculate Mean: First, let's find the mean of the data.Mean = (81+79+82+83+80+78+80+87+82+82)/10Mean = 814/10Mean = 81.4
Deviation and Sum: Next, we calculate each value's deviation from the mean, square those deviations, and sum them up.Sum of squared deviations = (81−81.4)2+(79−81.4)2+(82−81.4)2+(83−81.4)2+(80−81.4)2+(78−81.4)2+(80−81.4)2+(87−81.4)2+(82−81.4)2+(82−81.4)2Sum of squared deviations = (−0.4)2+(−2.4)2+(0.6)2+(1.6)2+(−1.4)2+(−3.4)2+(−1.4)2+(5.6)2+(0.6)2+(0.6)2Sum of squared deviations = 0.16+5.76+0.36+2.56+1.96+11.56+1.96+31.36+0.36+0.36Sum of squared deviations = $\(55\).\(44\)
Calculate Variance: Now, we find the variance by dividing the sum of squared deviations by the degrees of freedom.\(\newline\)Degrees of freedom = \(n - 1\)\(\newline\)Degrees of freedom = \(10 - 1\)\(\newline\)Degrees of freedom = \(9\)\(\newline\)Variance = Sum of squared deviations / Degrees of freedom\(\newline\)Variance = \(55.44 / 9\)\(\newline\)Variance = \(6.16\)
Find Standard Deviation: To get the standard deviation, we take the square root of the variance.\(\newline\)Standard deviation = \(\sqrt{\text{Variance}}\)\(\newline\)Standard deviation = \(\sqrt{6.16}\)\(\newline\)Standard deviation = \(2.48\)
Coefficient of Variation: The coefficient of variation is calculated by dividing the standard deviation by the mean and multiplying by \(100\) to get a percentage.\(\newline\)Coefficient of variation = \((\text{Standard deviation} / \text{Mean}) \times 100\)\(\newline\)Coefficient of variation = \((2.48 / 81.4) \times 100\)\(\newline\)Coefficient of variation = \(3.05\%\)
Calculate Q\(3\): For the third quartile (\(Q_3\)), we need to find the value below which \(75\%\) of the data lies. Since we have \(10\) data points, the position of \(Q_3\) is the \(7.5\)th value.\(\newline\)We'll need to arrange the data in ascending order and then find the value at the \(7.5\)th position.\(\newline\)Ordered data: \(78\), \(79\), \(80\), \(80\), \(75\%\)\(0\), \(75\%\)\(1\), \(75\%\)\(1\), \(75\%\)\(1\), \(75\%\)\(4\), \(75\%\)\(5\)\(\newline\)\(Q_3\) is between the \(75\%\)\(7\)th and \(75\%\)\(8\)th value, so we average them.\(\newline\)\(75\%\)\(9\)\(\newline\)\(10\)\(0\)
Find \(D_6\): The sixth decile (\(D_6\)) is the value below which \(60\%\) of the data lies. The position of \(D_6\) is the \(6\)th value in the ordered data.\(\newline\)\(D_6 = 82\)
Calculate \(P_{45}\): For the \(45\)th percentile (\(P_{45}\)), we find the value below which \(45\%\) of the data lies. The position of \(P_{45}\) is the \(4.5\)th value.\(\newline\)\(P_{45}\) is between the \(4\)th and \(5\)th value, so we average them.\(\newline\)\(P_{45} = \frac{80 + 81}{2}\)\(\newline\)\(P_{45} = 80.5\)