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Berikut data tinggi bibit pohon (cm) di kampus Poltesa : 81,79,82,83,80,78,80,87,82,8281, 79, 82, 83, 80, 78, 80, 87, 82, 82 Hitunglah: 11. simpangan baku 22. varian 33. derajat bebas 44. koefisien keragaman 55. Kuartil 33 66. desil 66 77. Persentil 4545

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Q. Berikut data tinggi bibit pohon (cm) di kampus Poltesa : 81,79,82,83,80,78,80,87,82,8281, 79, 82, 83, 80, 78, 80, 87, 82, 82 Hitunglah: 11. simpangan baku 22. varian 33. derajat bebas 44. koefisien keragaman 55. Kuartil 33 66. desil 66 77. Persentil 4545
  1. Calculate Mean: First, let's find the mean of the data.\newlineMean = (81+79+82+83+80+78+80+87+82+82)/10(81 + 79 + 82 + 83 + 80 + 78 + 80 + 87 + 82 + 82) / 10\newlineMean = 814/10814 / 10\newlineMean = 81.481.4
  2. Deviation and Sum: Next, we calculate each value's deviation from the mean, square those deviations, and sum them up.\newlineSum of squared deviations = (8181.4)2+(7981.4)2+(8281.4)2+(8381.4)2+(8081.4)2+(7881.4)2+(8081.4)2+(8781.4)2+(8281.4)2+(8281.4)2(81 - 81.4)^2 + (79 - 81.4)^2 + (82 - 81.4)^2 + (83 - 81.4)^2 + (80 - 81.4)^2 + (78 - 81.4)^2 + (80 - 81.4)^2 + (87 - 81.4)^2 + (82 - 81.4)^2 + (82 - 81.4)^2\newlineSum of squared deviations = (0.4)2+(2.4)2+(0.6)2+(1.6)2+(1.4)2+(3.4)2+(1.4)2+(5.6)2+(0.6)2+(0.6)2(-0.4)^2 + (-2.4)^2 + (0.6)^2 + (1.6)^2 + (-1.4)^2 + (-3.4)^2 + (-1.4)^2 + (5.6)^2 + (0.6)^2 + (0.6)^2\newlineSum of squared deviations = 0.16+5.76+0.36+2.56+1.96+11.56+1.96+31.36+0.36+0.360.16 + 5.76 + 0.36 + 2.56 + 1.96 + 11.56 + 1.96 + 31.36 + 0.36 + 0.36\newlineSum of squared deviations = $\(55\).\(44\)
  3. Calculate Variance: Now, we find the variance by dividing the sum of squared deviations by the degrees of freedom.\(\newline\)Degrees of freedom = \(n - 1\)\(\newline\)Degrees of freedom = \(10 - 1\)\(\newline\)Degrees of freedom = \(9\)\(\newline\)Variance = Sum of squared deviations / Degrees of freedom\(\newline\)Variance = \(55.44 / 9\)\(\newline\)Variance = \(6.16\)
  4. Find Standard Deviation: To get the standard deviation, we take the square root of the variance.\(\newline\)Standard deviation = \(\sqrt{\text{Variance}}\)\(\newline\)Standard deviation = \(\sqrt{6.16}\)\(\newline\)Standard deviation = \(2.48\)
  5. Coefficient of Variation: The coefficient of variation is calculated by dividing the standard deviation by the mean and multiplying by \(100\) to get a percentage.\(\newline\)Coefficient of variation = \((\text{Standard deviation} / \text{Mean}) \times 100\)\(\newline\)Coefficient of variation = \((2.48 / 81.4) \times 100\)\(\newline\)Coefficient of variation = \(3.05\%\)
  6. Calculate Q\(3\): For the third quartile (\(Q_3\)), we need to find the value below which \(75\%\) of the data lies. Since we have \(10\) data points, the position of \(Q_3\) is the \(7.5\)th value.\(\newline\)We'll need to arrange the data in ascending order and then find the value at the \(7.5\)th position.\(\newline\)Ordered data: \(78\), \(79\), \(80\), \(80\), \(75\%\)\(0\), \(75\%\)\(1\), \(75\%\)\(1\), \(75\%\)\(1\), \(75\%\)\(4\), \(75\%\)\(5\)\(\newline\)\(Q_3\) is between the \(75\%\)\(7\)th and \(75\%\)\(8\)th value, so we average them.\(\newline\)\(75\%\)\(9\)\(\newline\)\(10\)\(0\)
  7. Find \(D_6\): The sixth decile (\(D_6\)) is the value below which \(60\%\) of the data lies. The position of \(D_6\) is the \(6\)th value in the ordered data.\(\newline\)\(D_6 = 82\)
  8. Calculate \(P_{45}\): For the \(45\)th percentile (\(P_{45}\)), we find the value below which \(45\%\) of the data lies. The position of \(P_{45}\) is the \(4.5\)th value.\(\newline\)\(P_{45}\) is between the \(4\)th and \(5\)th value, so we average them.\(\newline\)\(P_{45} = \frac{80 + 81}{2}\)\(\newline\)\(P_{45} = 80.5\)

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