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Below is the problem statement for an exercise asking you to go through a hypothesis test. Which calculator function are you going to use to find the test statistic or p-value?
You wish to test the following claim 
(H_(a)) at a significance level of 
alpha=0.05.

{:[H_(o):p=0.42],[H_(a):p > 0.42]:}
You obtain a sample of size 
n=143 in which there are 73 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.
T-test
1-PropZint
Zinterval
1-PropZtest
Z-Test

Below is the problem statement for an exercise asking you to go through a hypothesis test. Which calculator function are you going to use to find the test statistic or p-value?\newlineYou wish to test the following claim (Ha) \left(\mathrm{H}_{\mathrm{a}}\right) at a significance level of α=0.05 \alpha=0.05 .\newlineHo:p=0.42Ha:p>0.42 \begin{array}{l} \mathrm{H}_{\mathrm{o}}: p=0.42 \\ \mathrm{H}_{\mathrm{a}}: p>0.42 \end{array} \newlineYou obtain a sample of size n=143 n=143 in which there are 7373 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.\newlineT-test\newline11-PropZint\newlineZinterval\newline11-PropZtest\newlineZ-Test

Full solution

Q. Below is the problem statement for an exercise asking you to go through a hypothesis test. Which calculator function are you going to use to find the test statistic or p-value?\newlineYou wish to test the following claim (Ha) \left(\mathrm{H}_{\mathrm{a}}\right) at a significance level of α=0.05 \alpha=0.05 .\newlineHo:p=0.42Ha:p>0.42 \begin{array}{l} \mathrm{H}_{\mathrm{o}}: p=0.42 \\ \mathrm{H}_{\mathrm{a}}: p>0.42 \end{array} \newlineYou obtain a sample of size n=143 n=143 in which there are 7373 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.\newlineT-test\newline11-PropZint\newlineZinterval\newline11-PropZtest\newlineZ-Test
  1. Claim and Sample Information: We have a claim that the population proportion pp is greater than 0.420.42, and we want to test this claim using a sample of size n=143n=143 with 7373 successes.
  2. Calculator Function Selection: Since we're testing a single proportion without continuity correction and using normal approximation, the appropriate calculator function is "11-PropZtest".
  3. Input for Calculator: We input the following into the calculator: p0p_0 (hypothesized proportion) = 0.420.42, xx (number of successes) = 7373, nn (sample size) = 143143, and we select the alternative hypothesis "p>0.42p > 0.42".

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