Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

$Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 1ooth if necessary. {:[" 1-Var-Stats "],[ bar(x)=270],[Sigma x=1890],[Sigmax^(2)=512150],[Sx=17.5594229214],[sigma x=16.2568666811],[n=7],[minX=240],[Q_(1)=257],[Med^(2)=274],[Q_(3)=282],[maxX=291]:} Answer:$

Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest $1$ ooth if necessary. $\newline$ $\begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=270 \\ \Sigma x=1890 \\ \Sigma x^{2}=512150 \\ S x=17.5594229214 \\ \sigma x=16.2568666811 \\ n=7 \\ \operatorname{minX}=240 \\ \mathrm{Q}_{1}=257 \\ \mathrm{Med}^{2}=274 \\ \mathrm{Q}_{3}=282 \\ \max \mathrm{X}=291 \end{array}$ $\newline$ Answer:

View step-by-step help

Home

Math Problems

Grade 8

Solve one-step and two-step equations: word problems

Full solution

Q. Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest

1

ooth if necessary.

\newline

\begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=270 \\ \Sigma x=1890 \\ \Sigma x^{2}=512150 \\ S x=17.5594229214 \\ \sigma x=16.2568666811 \\ n=7 \\ \operatorname{minX}=240 \\ \mathrm{Q}_{1}=257 \\ \mathrm{Med}^{2}=274 \\ \mathrm{Q}_{3}=282 \\ \max \mathrm{X}=291 \end{array}

\newline

Answer:

Identify symbol for population standard deviation: Identify the symbol for population standard deviation in the calculator output. $\newline$ The symbol for population standard deviation in the calculator output is ＂ $\sigma_x$ ＂. This is the value we are looking for.
Locate value in calculator output: Locate the value of the population standard deviation in the calculator output. $\newline$ The value given for ＂sigma x＂ in the output is $16.2568666811$ .
Round to nearest hundredth: Round the population standard deviation to the nearest hundredth. $\newline$ To round to the nearest hundredth, we look at the third decimal place. If it is $5$ or more, we round up. If it is less than $5$ , we round down. The third decimal place of $16.2568666811$ is $6$ , so we round up the second decimal place from $5$ to $6$ . $\newline$ The rounded population standard deviation is $16.26$ .