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Let’s check out your problem:
X
Y
‾
≅
V
W
‾
,
∠
Y
≅
∠
V
\overline{X Y} \cong \overline{V W}, \angle Y \cong \angle V
X
Y
≅
VW
,
∠
Y
≅
∠
V
, and
∠
S
W
Y
≅
∠
U
X
V
\angle S W Y \cong \angle U X V
∠
S
WY
≅
∠
U
X
V
. Complete the proof that
△
S
W
Y
≅
△
U
X
V
\triangle S W Y \cong \triangle U X V
△
S
WY
≅
△
U
X
V
.
\newline
\begin{tabular}{|l|l|l|}
\newline
\hline & Statement & Reason \\
\newline
\hline
1
1
1
&
X
Y
‾
≅
V
W
‾
\overline{X Y} \cong \overline{V W}
X
Y
≅
VW
& Given \\
\newline
2
2
2
&
∠
Y
≅
∠
V
\angle Y \cong \angle V
∠
Y
≅
∠
V
& Given \\
\newline
3
3
3
&
∠
S
W
Y
≅
∠
U
X
V
\angle S W Y \cong \angle U X V
∠
S
WY
≅
∠
U
X
V
& Given \\
\newline
4
4
4
&
W
Y
=
X
Y
+
W
X
W Y=X Y+W X
WY
=
X
Y
+
W
X
& \\
\newline
5
5
5
&
V
X
=
V
W
+
W
X
V X=V W+W X
V
X
=
VW
+
W
X
& \\
\newline
6
6
6
&
W
Y
=
V
W
+
W
X
W Y=V W+W X
WY
=
VW
+
W
X
& \\
\newline
7
7
7
&
V
X
=
W
Y
V X=W Y
V
X
=
WY
& \\
\newline
8
8
8
&
△
S
W
Y
≅
△
U
X
V
\triangle S W Y \cong \triangle U X V
△
S
WY
≅
△
U
X
V
& \\
\newline
\hline
\newline
\end{tabular}
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Home
Math Problems
Calculus
Euler's method
Full solution
Q.
X
Y
‾
≅
V
W
‾
,
∠
Y
≅
∠
V
\overline{X Y} \cong \overline{V W}, \angle Y \cong \angle V
X
Y
≅
VW
,
∠
Y
≅
∠
V
, and
∠
S
W
Y
≅
∠
U
X
V
\angle S W Y \cong \angle U X V
∠
S
WY
≅
∠
U
X
V
. Complete the proof that
△
S
W
Y
≅
△
U
X
V
\triangle S W Y \cong \triangle U X V
△
S
WY
≅
△
U
X
V
.
\newline
\begin{tabular}{|l|l|l|}
\newline
\hline & Statement & Reason \\
\newline
\hline
1
1
1
&
X
Y
‾
≅
V
W
‾
\overline{X Y} \cong \overline{V W}
X
Y
≅
VW
& Given \\
\newline
2
2
2
&
∠
Y
≅
∠
V
\angle Y \cong \angle V
∠
Y
≅
∠
V
& Given \\
\newline
3
3
3
&
∠
S
W
Y
≅
∠
U
X
V
\angle S W Y \cong \angle U X V
∠
S
WY
≅
∠
U
X
V
& Given \\
\newline
4
4
4
&
W
Y
=
X
Y
+
W
X
W Y=X Y+W X
WY
=
X
Y
+
W
X
& \\
\newline
5
5
5
&
V
X
=
V
W
+
W
X
V X=V W+W X
V
X
=
VW
+
W
X
& \\
\newline
6
6
6
&
W
Y
=
V
W
+
W
X
W Y=V W+W X
WY
=
VW
+
W
X
& \\
\newline
7
7
7
&
V
X
=
W
Y
V X=W Y
V
X
=
WY
& \\
\newline
8
8
8
&
△
S
W
Y
≅
△
U
X
V
\triangle S W Y \cong \triangle U X V
△
S
WY
≅
△
U
X
V
& \\
\newline
\hline
\newline
\end{tabular}
Given:
1
1
1
.
X
Y
‾
≈
V
W
‾
\overline{XY} \approx \overline{VW}
X
Y
≈
VW
\newline
Reason: Given
Given:
2
2
2
.
∠
Y
≅
∠
V
\angle Y \cong \angle V
∠
Y
≅
∠
V
\newline
Reason: Given
Given:
3
3
3
.
∠
S
W
Y
≅
∠
U
X
V
\angle SWY \cong \angle UXV
∠
S
WY
≅
∠
U
X
V
\newline
Reason: Given
Segment Addition Postulate:
W
Y
=
X
Y
+
W
X
WY=XY+WX
WY
=
X
Y
+
W
X
\newline
Reason: Segment Addition Postulate
More problems from Euler's method
Question
Let
f
(
x
)
=
x
3
−
6
x
2
+
12
x
f(x)=x^{3}-6 x^{2}+12 x
f
(
x
)
=
x
3
−
6
x
2
+
12
x
and let
c
c
c
be the number that satisfies the Mean Value Theorem for
f
f
f
on the interval
[
0
,
3
]
[0,3]
[
0
,
3
]
.
\newline
What is
c
c
c
?
\newline
Choose
1
1
1
answer:
\newline
(A)
0
0
0
\newline
(B)
1
1
1
\newline
(C)
2
2
2
\newline
(D)
3
3
3
Get tutor help
Posted 2 months ago
Question
Let
g
(
x
)
=
x
3
+
12
x
2
+
36
x
g(x)=x^{3}+12 x^{2}+36 x
g
(
x
)
=
x
3
+
12
x
2
+
36
x
and let
c
c
c
be the number that satisfies the Mean Value Theorem for
g
g
g
on the interval
−
8
≤
x
≤
−
2
-8 \leq x \leq-2
−
8
≤
x
≤
−
2
.
\newline
What is
c
c
c
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
7
-7
−
7
\newline
(B)
−
6
-6
−
6
\newline
(C)
−
3
-3
−
3
\newline
(D)
−
1
-1
−
1
Get tutor help
Posted 2 months ago
Question
Let
h
(
x
)
=
x
3
−
6
x
2
−
10
x
h(x)=x^{3}-6 x^{2}-10 x
h
(
x
)
=
x
3
−
6
x
2
−
10
x
and let
c
c
c
be the number that satisfies the Mean Value Theorem for
h
h
h
on the interval
[
−
4
,
5
]
[-4,5]
[
−
4
,
5
]
.
\newline
What is
c
c
c
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
2
-2
−
2
\newline
(B)
−
1
-1
−
1
\newline
(C)
1
1
1
\newline
(D)
3
3
3
Get tutor help
Posted 1 month ago
Question
Let
g
(
x
)
=
2
x
3
−
21
x
2
+
60
x
g(x)=2 x^{3}-21 x^{2}+60 x
g
(
x
)
=
2
x
3
−
21
x
2
+
60
x
.
\newline
What is the absolute maximum value of
g
g
g
over the closed interval
[
0
,
6
]
[0,6]
[
0
,
6
]
?
\newline
Choose
1
1
1
answer:
\newline
(A)
25
25
25
\newline
(B)
42
42
42
\newline
(C)
36
36
36
\newline
(D)
52
52
52
Get tutor help
Posted 1 month ago
Question
Let
f
(
x
)
=
2
x
3
+
21
x
2
+
36
x
f(x)=2 x^{3}+21 x^{2}+36 x
f
(
x
)
=
2
x
3
+
21
x
2
+
36
x
.
\newline
What is the absolute maximum value of
f
f
f
over the closed interval
[
−
8
,
0
]
[-8,0]
[
−
8
,
0
]
?
\newline
Choose
1
1
1
answer:
\newline
(A)
32
32
32
\newline
(B)
180
\mathbf{1 8 0}
180
\newline
(C)
108
\mathbf{1 0 8}
108
\newline
(D)
0
0
0
Get tutor help
Posted 2 months ago
Question
Let
h
(
x
)
=
x
3
+
6
x
2
+
2
h(x)=x^{3}+6 x^{2}+2
h
(
x
)
=
x
3
+
6
x
2
+
2
.
\newline
What is the absolute minimum value of
h
h
h
over the closed interval
−
6
≤
x
≤
2
-6 \leq x \leq 2
−
6
≤
x
≤
2
?
\newline
Choose
1
1
1
answer:
\newline
(A)
34
34
34
\newline
(B)
−
34
-34
−
34
\newline
(C)
2
2
2
\newline
(D)
−
2
-2
−
2
Get tutor help
Posted 2 months ago
Question
1
,
000
=
20
z
2
1,000=20z^{2}
1
,
000
=
20
z
2
\newline
How many distinct real solutions does the given equation have?
\newline
Choose
1
1
1
answer:
\newline
(A)
0
0
0
\newline
(B)
1
1
1
\newline
(C)
2
2
2
\newline
(D)
4
4
4
Get tutor help
Posted 2 months ago
Question
Dante commutes to work
4
4
4
mornings a week. For his commute each morning, he walks for
10
10
10
minutes, waits and rides the bus for
x
x
x
minutes, and waits and rides the train for
y
y
y
minutes. If Dante spends at least
3.5
3.5
3.5
hours on his morning commute each week, which of the following inequalities best describes Dante's weekly morning commute?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
+
y
+
10
≥
3.5
(
60
)
x+y+10 \geq 3.5(60)
x
+
y
+
10
≥
3.5
(
60
)
\newline
(B)
x
+
y
+
10
≥
3.5
(
60
)
(
4
)
x+y+10 \geq 3.5(60)(4)
x
+
y
+
10
≥
3.5
(
60
)
(
4
)
\newline
(C)
4
(
x
+
y
)
+
10
≥
3.5
(
60
)
4(x+y)+10 \geq 3.5(60)
4
(
x
+
y
)
+
10
≥
3.5
(
60
)
\newline
(D)
4
(
x
+
y
+
10
)
≥
3.5
(
60
)
4(x+y+10) \geq 3.5(60)
4
(
x
+
y
+
10
)
≥
3.5
(
60
)
Get tutor help
Posted 2 months ago
Question
1
3
x
+
3
y
=
4
\frac{1}{3}x+3y=4
3
1
x
+
3
y
=
4
\newline
2
x
−
4
=
2
y
2x-4=2y
2
x
−
4
=
2
y
\newline
Consider the given system of equations. If
(
x
,
y
)
(x,y)
(
x
,
y
)
is the solution to the system, then what is the value of
x
−
y
x-y
x
−
y
?
\newline
□
\square
□
Get tutor help
Posted 1 month ago
Question
2
2
2
) Solve
x
2
−
4
=
x
3
+
2
\frac{x}{2}-4=\frac{x}{3}+2
2
x
−
4
=
3
x
+
2
\newline
a) List the title for this type of problem(
10
10
10
)
\newline
b) List the section where you would find nc
\newline
c) List the procedure or rules written in yo
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Posted 2 months ago