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b Clevate
(-4**6)×5quad(3**4

z
(2) If
a**b=a-b^(3)1 then
21**z=
Now elevele:
(2//**2)**5
(3) If
p**q=2p^(2)-3q What is
(1**5)**3) ?

b Clevate $(-4 * 6) \times 5 \quad(3 * 4$ $\newline$ $z$ $\newline$ ( $2$ ) If $a * b=a-b^{3} 1$ then $21 * z=$ $\newline$ Now elevele: $(2 / * 2) * 5$ $\newline$ ( $3$ ) If $p * q=2 p^{2}-3 q$ What is $(1 * 5) * 3)$ ?

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Divide numbers written in scientific notation

Full solution

Q. b Clevate

(-4 * 6) \times 5 \quad(3 * 4

\newline

z

\newline

(

2

) If

a * b=a-b^{3} 1

then

21 * z=

\newline

Now elevele:

(2 / * 2) * 5

\newline

(

3

) If

p * q=2 p^{2}-3 q

What is

(1 * 5) * 3)

?

Simplify Expression: First, let's simplify $(-4^6)\times 5$ .
$(-4^6)$ means $-4$ raised to the power of $6$ .
$(-4)^6 = (-4)\times(-4)\times(-4)\times(-4)\times(-4)\times(-4) = 4096$ , because a negative number raised to an even power is positive.
Now multiply $4096$ by $5$ .
$4096 \times 5 = 20480$ .
Solve Equation: Next, let's solve the equation $a^b=a-b^{3}+1$ for $21^z$ . This seems like a typo, but let's assume it means $a^b=a-b^3+1$ . So, $21^z = 21-z^3+1$ . But we don't have a value for $z$ , so we can't solve this further.

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