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b)
16-(r+2)=10+3(r-7)=>

b) $16-(r+2)=10+3(r-7) \Rightarrow$

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Solve equations with the distributive property

Full solution

Q. b)

16-(r+2)=10+3(r-7) \Rightarrow

Simplify Equation: Simplify both sides of the equation. $\newline$ On the left side, distribute the negative sign inside the parentheses. $\newline$ $16 - r - 2 = 10 + 3(r - 7)$ $\newline$ Combine like terms on the left side. $\newline$ $14 - r = 10 + 3(r - 7)$
Distribute and Combine: Distribute the $3$ on the right side of the equation. $14 - r = 10 + 3r - 21$ Combine like terms on the right side. $14 - r = 3r - 11$
Add and Combine: Add $r$ to both sides to get all the $r$ terms on one side. $\newline$ $14 - r + r = 3r - 11 + r$ $\newline$ $14 = 4r - 11$
Isolate r Term: Add $11$ to both sides to isolate the term with $r$ . $\newline$ $14 + 11 = 4r - 11 + 11$ $\newline$ $25 = 4r$
Solve for r: Divide both sides by $4$ to solve for r. $\newline$ $\frac{25}{4} = \frac{4r}{4}$ $\newline$ $6.25 = r$

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