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Ave
Grade
Thersdry
Math

1(1)/(21)÷(d)/( 10)=-

2(b)/(9)÷(1)/(2)=
3.1

Ave\newlineGrade\newlineThersdry\newlineMath\newline1121÷d10= 1 \frac{1}{21} \div \frac{d}{10}=- \newline2b9÷12= 2 \frac{b}{9} \div \frac{1}{2}= \newline33.11

Full solution

Q. Ave\newlineGrade\newlineThersdry\newlineMath\newline1121÷d10= 1 \frac{1}{21} \div \frac{d}{10}=- \newline2b9÷12= 2 \frac{b}{9} \div \frac{1}{2}= \newline33.11
  1. Solve for d: First, let's solve for d.\newline121÷d10=\frac{1}{21} \div \frac{d}{10} = -\newlineConvert mixed number to improper fraction: 1121=21+121=22211\frac{1}{21} = \frac{21 + 1}{21} = \frac{22}{21}.
  2. Divide by dd: Now, divide by d10\frac{d}{10}.2221÷d10=2221×10d=22021d\frac{22}{21} \div \frac{d}{10} = \frac{22}{21} \times \frac{10}{d} = \frac{220}{21d}.
  3. Set equation equal to 11: To find dd, set the equation equal to 11 (since the problem has a dash which might mean 11).\newline22021d=1\frac{220}{21d} = 1.
  4. Isolate dd: Multiply both sides by 21d21d to isolate dd.220=21d220 = 21d.
  5. Solve for dd: Divide both sides by 2121 to solve for dd.d=22021d = \frac{220}{21}.
  6. Solve for b: Now, let's solve for b. 2(b)9÷12=3.1\frac{2(b)}{9} \div \frac{1}{2} = 3.1
  7. Multiply to isolate bb: Multiply both sides by 92\frac{9}{2} to isolate bb.2(b)992=3.192\frac{2(b)}{9} \cdot \frac{9}{2} = 3.1 \cdot \frac{9}{2}.
  8. Simplify the equation: Simplify the equation. b=3.1×(92)b = 3.1 \times \left(\frac{9}{2}\right).
  9. Calculate bb: Calculate the value of bb.b=3.1×4.5b = 3.1 \times 4.5.
  10. Final value of b: b=13.95b = 13.95.