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At the end of the year, cars made in the current year are marked down to make room for next year's models. One particular model has a sale price of $20,727\$20,727, which is 10%10\% less than it sold for when it was new. What was the original price of the vehicle?\newline$\$____

Full solution

Q. At the end of the year, cars made in the current year are marked down to make room for next year's models. One particular model has a sale price of $20,727\$20,727, which is 10%10\% less than it sold for when it was new. What was the original price of the vehicle?\newline$\$____
  1. Understand Problem: Understand the problem and set up the equation.\newlineThe car's sale price is $20,727\$20,727 after a 1010\% reduction. Let the original price be xx.\newlineSale Price = Original Price - (1010\% of Original Price)\newline$20,727=x(0.10×x)\$20,727 = x - (0.10 \times x)
  2. Set Up Equation: Simplify the equation to solve for xx.\newline$20,727=x0.10x\$20,727 = x - 0.10x\newline$20,727=0.90x\$20,727 = 0.90x
  3. Simplify Equation: Isolate xx to find the original price.x=$(20,727)0.90x = \frac{\$(20,727)}{0.90}x=$(23,030)x = \$(23,030)

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