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CHEM Quiz - chap 21 and 30
7 of 14
POSSIBLE POINTS: 10

0.984M sodium hydroxide is placed in a buret and titrated with 
25.00mL of sulfuric acid. The initial buret reading is 
3.45mL and the final reading is 
25.64mL. What is the concentration of sulfuric acid? 
◻ Show all your work. (10 pts)
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at Apr 1313\newlineAA\newlinescholars.veritaspress.com\newlineSearch Red Tops For Women | SHEIN USA\newline(33) Schoology\newlineitas\newlineCOURSES\newlineGROUPS\newlineRESOURCES\newlineGRADES\newlineCHEM Quiz - chap 2121 and 3030\newline77 of 1414\newlinePOSSIBLE POINTS: 1010\newline0.984M 0.984 \mathrm{M} sodium hydroxide is placed in a buret and titrated with 25.00 mL 25.00 \mathrm{~mL} of sulfuric acid. The initial buret reading is 3.45 mL 3.45 \mathrm{~mL} and the final reading is 25.64 mL 25.64 \mathrm{~mL} . What is the concentration of sulfuric acid? \square Show all your work. (1010 pts)\newline22\newline33\newline44\newline55\newline66\newline77\newline88\newline99\newline1010\newline1111

Full solution

Q. at Apr 1313\newlineAA\newlinescholars.veritaspress.com\newlineSearch Red Tops For Women | SHEIN USA\newline(33) Schoology\newlineitas\newlineCOURSES\newlineGROUPS\newlineRESOURCES\newlineGRADES\newlineCHEM Quiz - chap 2121 and 3030\newline77 of 1414\newlinePOSSIBLE POINTS: 1010\newline0.984M 0.984 \mathrm{M} sodium hydroxide is placed in a buret and titrated with 25.00 mL 25.00 \mathrm{~mL} of sulfuric acid. The initial buret reading is 3.45 mL 3.45 \mathrm{~mL} and the final reading is 25.64 mL 25.64 \mathrm{~mL} . What is the concentration of sulfuric acid? \square Show all your work. (1010 pts)\newline22\newline33\newline44\newline55\newline66\newline77\newline88\newline99\newline1010\newline1111
  1. Calculate Volume NaOH: Calculate the volume of sodium hydroxide used in the titration by subtracting the initial buret reading from the final buret reading.\newlineVolume NaOH =Final buret readingInitial buret reading= \text{Final buret reading} - \text{Initial buret reading}\newlineVolume NaOH =25.64mL3.45mL= 25.64 \, \text{mL} - 3.45 \, \text{mL}\newlineVolume NaOH =22.19mL= 22.19 \, \text{mL}
  2. Convert to Liters: Convert the volume of sodium hydroxide from mL to L because concentration is given in moles per liter (M).Volume NaOH (L)=Volume NaOH (mL)1000\text{Volume NaOH (L)} = \frac{\text{Volume NaOH (mL)}}{1000}Volume NaOH (L)=22.19mL1000\text{Volume NaOH (L)} = \frac{22.19 \, \text{mL}}{1000}Volume NaOH (L)=0.02219L\text{Volume NaOH (L)} = 0.02219 \, \text{L}
  3. Find Moles of NaOH: Use the molarity of sodium hydroxide and its volume to find the moles of sodium hydroxide.\newlineMoles NaOH == Molarity NaOH * Volume NaOH (L)\newlineMoles NaOH = \(0.984984 \, M * 00.0221902219 \, L\newlineMoles NaOH = 00.0218402184 \) moles
  4. Write Chemical Equation: Write the balanced chemical equation for the reaction between sodium hydroxide and sulfuric acid.\newlineNaOH+H2SO4Na2SO4+2H2O\text{NaOH} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}

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