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At a school fair, the spinner represented in the accompanying diagram is spun twice. What is the probability that it will land in section 
G the first time and then in section 
B the second time?

1313. At a school fair, the spinner represented in the accompanying diagram is spun twice. What is the probability that it will land in section G G the first time and then in section B B the second time?

Full solution

Q. 1313. At a school fair, the spinner represented in the accompanying diagram is spun twice. What is the probability that it will land in section G G the first time and then in section B B the second time?
  1. Determine Total Sections: First, we need to determine the total number of sections on the spinner. Without the accompanying diagram, we cannot know the exact number of sections. However, for the purpose of this example, let's assume that the spinner is divided into 88 equal sections, with one section labeled GG and one section labeled BB.
  2. Calculate Probability of G: Next, we calculate the probability of the spinner landing on section GG on the first spin. Since there is only one section GG out of 88 total sections, the probability is 18\frac{1}{8}.
  3. Calculate Probability of B: Now, we calculate the probability of the spinner landing on section B on the second spin. Assuming that the outcome of the first spin does not affect the second spin (the spinner is fair and has no memory), the probability remains the same for the second spin. Therefore, the probability of landing on section B is also 18\frac{1}{8}.
  4. Find Combined Probability: To find the combined probability of both events happening in sequence (landing on G first and then on B), we multiply the probabilities of the two independent events. \newlineProbability of G then B = (Probability of G) ×\times (Probability of B) = 18\frac{1}{8} ×\times 18\frac{1}{8} = 164\frac{1}{64}.

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