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At a carnival, there is a game where you can draw one of 2020 balls from a bucket. The balls are numbered from 11 to 2020. If the number on the ball is even, you win $11\$11. If the number on the ball is odd, you win nothing. If you play the game, what is the expected payoff?\newline$\$____

Full solution

Q. At a carnival, there is a game where you can draw one of 2020 balls from a bucket. The balls are numbered from 11 to 2020. If the number on the ball is even, you win $11\$11. If the number on the ball is odd, you win nothing. If you play the game, what is the expected payoff?\newline$\$____
  1. Calculate probability of even: question_prompt: What's the expected payoff for the carnival game where you draw numbered balls from a bucket?
  2. Calculate probability of odd: Step 11: Calculate the probability of drawing an even numbered ball. There are 1010 even numbers in 11 to 2020, so the probability is 1020\frac{10}{20} or 12\frac{1}{2}.
  3. Calculate expected payoff for even: Step 22: Calculate the probability of drawing an odd numbered ball. There are also 1010 odd numbers in 11 to 2020, so the probability is 1020\frac{10}{20} or 12\frac{1}{2}.
  4. Calculate expected payoff for odd: Step 33: Calculate the expected payoff for drawing an even numbered ball. Since the payoff is $11\$11 for an even number, multiply the probability by the payoff: (1/2)×$11=$5.50(1/2) \times \$11 = \$5.50.
  5. Find total expected payoff: Step 44: Calculate the expected payoff for drawing an odd numbered ball. Since there's no payoff for an odd number, multiply the probability by 00: 12\frac{1}{2} * $0\$0 = $0\$0.
  6. Find total expected payoff: Step 44: Calculate the expected payoff for drawing an odd numbered ball. Since there's no payoff for an odd number, multiply the probability by 00: (12)×($0)=($0)(\frac{1}{2}) \times (\$0) = (\$0). Step 55: Add the expected payoffs together to find the total expected payoff. ($5.50)(\$5.50) (even) + ($0)(\$0) (odd) = ($5.50)(\$5.50).

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