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Assuming 
x and 
y are both positive, write the following expression in simplest radical form.

2y^(2)sqrt(18x^(6)y^(4))
Answer:

Assuming x x and y y are both positive, write the following expression in simplest radical form.\newline2y218x6y4 2 y^{2} \sqrt{18 x^{6} y^{4}} \newlineAnswer:

Full solution

Q. Assuming x x and y y are both positive, write the following expression in simplest radical form.\newline2y218x6y4 2 y^{2} \sqrt{18 x^{6} y^{4}} \newlineAnswer:
  1. Factor and Identify Perfect Squares: First, let's factor the radicand (the number inside the square root) to see if any factors are perfect squares. 18x6y4\sqrt{18x^{6}y^{4}} can be broken down into 2×9×x6×y4\sqrt{2 \times 9 \times x^{6} \times y^{4}}. We know that 99 is a perfect square, x6x^{6} is a perfect square since 66 is an even number, and y4y^{4} is a perfect square since 44 is an even number.
  2. Take Square Roots of Perfect Squares: Now, let's take the square root of the perfect squares. 9=3\sqrt{9} = 3, x6=x3\sqrt{x^{6}} = x^{3}, and y4=y2\sqrt{y^{4}} = y^{2}. So, 18x6y4\sqrt{18x^{6}y^{4}} simplifies to 3x3y223x^{3}y^{2} \sqrt{2}.
  3. Multiply Outside Term: Next, we multiply the outside term 2y22y^{2} by the simplified square root term.\newline2y2×3x3y2×2=6x3y4×2.2y^{2} \times 3x^{3}y^{2} \times \sqrt{2} = 6x^{3}y^{4} \times \sqrt{2}.
  4. Simplify to Simplest Form: Finally, we have simplified the expression to its simplest radical form.\newlineThe expression 2y218x6y42y^{2}\sqrt{18x^{6}y^{4}} simplifies to 6x3y426x^{3}y^{4} \sqrt{2}.

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