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Assume that yy varies inversely with xx. If y=2y = 2 when x=20x = 20, find yy when x=5x = 5. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____

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Q. Assume that yy varies inversely with xx. If y=2y = 2 when x=20x = 20, find yy when x=5x = 5. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____
  1. Identify Inverse Variation: Inverse variation means y=kxy = \frac{k}{x}. We need to find kk using the given values.
  2. Find kk using given values: Substitute y=2y = 2 and x=20x = 20 into y=kxy = \frac{k}{x} to find kk. So, 2=k202 = \frac{k}{20}.
  3. Substitute values into equation: Multiply both sides by 2020 to solve for kk. 2×20=k2 \times 20 = k, which means k=40k = 40.
  4. Calculate kk: Now we have kk, so the equation is y=40xy = \frac{40}{x}. Let's find yy when x=5x = 5.
  5. Find yy when x=5x = 5: Substitute x=5x = 5 into y=40xy = \frac{40}{x}. So, y=405y = \frac{40}{5}.
  6. Find yy when x=5x = 5: Substitute x=5x = 5 into y=40xy = \frac{40}{x}. So, y=405y = \frac{40}{5}.Calculate yy. y=405=8y = \frac{40}{5} = 8.

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