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Assignment 9 - Avg value and arc len (1 point)
Find the average value of the functions on the given interval.
a) Average value of 
f(x)=x on 
[5,13] :

Assignment 99 - Avg value and arc len (11 point)\newlineFind the average value of the functions on the given interval.\newlinea) Average value of f(x)=x f(x)=x on [5,13] [5,13] :

Full solution

Q. Assignment 99 - Avg value and arc len (11 point)\newlineFind the average value of the functions on the given interval.\newlinea) Average value of f(x)=x f(x)=x on [5,13] [5,13] :
  1. Define formula: Step 11: Define the formula for the average value of a function on an interval [a,b][a, b].\newlineThe formula is: Average value = 1(ba)abf(x)dx\frac{1}{(b-a)} \int_{a}^{b} f(x) \, dx.\newlineHere, f(x)=xf(x) = x and [a,b]=[5,13][a, b] = [5, 13].
  2. Calculate integral: Step 22: Calculate the integral of f(x)=xf(x) = x from 55 to 1313.513xdx=[x22]513=(1322)(522)=(1692)(252)=1442=72\int_{5}^{13} x \, dx = \left[\frac{x^2}{2}\right]_{5}^{13} = \left(\frac{13^2}{2}\right) - \left(\frac{5^2}{2}\right) = \left(\frac{169}{2}\right) - \left(\frac{25}{2}\right) = \frac{144}{2} = 72.
  3. Plug into formula: Step 33: Plug the integral value into the average value formula.\newlineAverage value = (1/(135))×72=(1/8)×72=9(1/(13-5)) \times 72 = (1/8) \times 72 = 9.

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